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Aneli [31]
2 years ago
11

Account a and b each start with $400. If account a earn $45 each year and account b earns 5% of its value each year when will ac

count b have more money than account a
Mathematics
1 answer:
seropon [69]2 years ago
4 0

Answer:  T>2.185 year

Step-by-step explanation:

A=P\left ( 1+R/100\right )^{T}

A=Amount ,P=Principle , R=Rate , T=Time

CI=compound interest

CI=A-P

P=400\$  for each a and b

account earn each year by a=45\$

account b earns  5%%

find the time the value of b is more

45

445

445/400

\ln \left ( 445/400 \right )

.106609735

=2.1850

T>2.185 year

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First, let's look at what happens when we input smaller and smaller numbers

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