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Mazyrski [523]
3 years ago
14

At the beginning of a snowstorm, Evan had 3 inches of snow on his lawn. The snow then began to fall at a constant rate of 3 inch

es per hour. Assuming no snow was melting, how much snow would Evan have on his lawn 3 hours after the snow began to fall? How much snow would Evan have on his lawn after tt hours of snow falling?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

3+3tt=total amount of snow

Step-by-step explanation:

y=mx+b is used to show increase

In this case, b is the original 3 inches of snow. m is the constant growth, and x is tt, or the amount of time it is being compared to. y is the total.

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Klio2033 [76]
1.875 because ⅜ or 5 is 1.87 or 1.9 if you round it.
5 0
3 years ago
Read 2 more answers
Congress regulates corporate fuel economy and sets an annual gas mileage for cars. A company with a large fleet of cars hopes to
attashe74 [19]

Answer:

a) Null hypothesis:\mu \leq 30.2  

Alternative hypothesis:\mu > 30.2  

b) X \sim N(\mu=32.12, \sigma=4.83)

And the distribution for the random sample is given by:

\bar X \sim N(\mu=32.12, \frac{\sigma}{\sqrt{n}}=\frac{4.83}{\sqrt{50}}=0.683)

c) t=\frac{32.12-30.2}{\frac{4.83}{\sqrt{50}}}=2.81    

p_v =P(t_{(49)}>2.81)=0.0035  

d) If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly higher than 30.2.  

e) The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct. And for this case is a value to accept or reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

\bar X=32.12 represent the sample mean  

s=4.83 represent the sample standard deviation

n=50 sample size  

\mu_o =30.2 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

a. Define the parameter and state the hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 30.2 mpg, the system of hypothesis would be:  

Null hypothesis:\mu \leq 30.2  

Alternative hypothesis:\mu > 30.2  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

b. Define the sampling distribution (mean and standard deviation).

Let X the random variable who represent the variable of interest. And we know that the distribution for X is:

X \sim N(\mu=32.12, \sigma=4.83)

And the distribution for the random sample is given by:

\bar X \sim N(\mu=32.12, \frac{\sigma}{\sqrt{n}}=\frac{4.83}{\sqrt{50}}=0.683)

c. Perform the test and calculate P-value

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{32.12-30.2}{\frac{4.83}{\sqrt{50}}}=2.81    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=50-1=49  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(49)}>2.81)=0.0035  

d. State your conclusion.

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly higher than 30.2.  

e. Explain what the p-value means in this context.

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct. And for this case is a value to accept or reject the null hypothesis.

6 0
3 years ago
I’m a little confused with this? Can someone walk me through this?
mina [271]

Answer:

A. 5.8

Step-by-step explanation:

From the given graph d has two coordinates;

the first coordinates of d = (0, 0)

the second coordinate of d = (-3 , -5), that is x = -3 when traced up and y = -5 when traced horizontal

The distance between the two coordinates = distance of d;

distance \ between \ two \ coordinates = \sqrt{(x_2-x_1)^2 \ + \ (y_2-y_1)^2} \\\\d =  \sqrt{(-3-0)^2 \ + \ (-5-0)^2}\\\\d = \sqrt{9 \ + \ 25} \\\\d = \sqrt{34} \\\\d = 5.83\\\\d = 5.8

Option A is correct

6 0
3 years ago
Given the x intercept of (4,0) and y intercept of (0,-3) graph the points and find the slope of the line
Marina CMI [18]

Answer:

The slope is 3/4 and on a graph it would be 4 over to the right and 3 down.

4 0
3 years ago
Please please help please ASAP
Vedmedyk [2.9K]

Answer:

VT = 50√3 , PT = 50

Step-by-step explanation:

Given

PV = 100

With reference angle 60°

hypotenuse (h) = 100

perpendicular (p) = ?

Now

Sin 60° = p/h

√3 / 2 = p / 100

p = √3 * 100 / 2

p = 50√3

Also

With reference angle 30°

hypotenuse (h) = 100

perpendicular (p) = ?

sin 30° = p/h

1/2 = p / 100

p = 100 / 2

p = 50

Hope it will help :)

8 0
3 years ago
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