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ludmilkaskok [199]
4 years ago
6

): How many times longer is the diameter of a grain of sand than the diameter of the average cell in the human body? Show your w

ork.    Need help bad:(
Mathematics
1 answer:
Airida [17]4 years ago
4 0
<span>Approximately 25. Of the 5 grades of sand used in the United states, medium sand has particles ranging from 0.25 mm to 0.5 mm. For convenience, I'll use 0.5mm as the diameter of a grain of sand. Human cells range from a volume of 30 cubic micrometers (human sperm cell) up to 4 million micrometers (human egg cell). For the average human cell, I'll use an osteoblast with a volume of 4000 cubic micrometers or a diameter of 2x10^-5 meters. Now just take the diameter of a grain of sand and divide by the diameter of a human cell. 5 x 10^-4 / 2x10^-5 = 5/2 x 10^(-4 - -5) = 2.5x10^1 = 25 So the diameter of a grain of sand at 0.5 mm is approximately 25 times larger than that of a human cell at 0.02mm</span>
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write and solve an equation to show thw average number of calendars her 3rd period class sold peer week during the four week cha
kari74 [83]
If they sold 89 calendars over 4 weeks, the 'equation' would look like (x = average calendars sold over 4 weeks):
x =  \frac{89}{4}

If you solve it, you get:
22 \frac{1}{4}

Which is equal to 22.25. Hope this helps!
5 0
3 years ago
I need to know how to solve this problem because I’m very confused and it doesn’t explain what it is or how to do it in my textb
Lostsunrise [7]

Answer:

x1 = -4; x2 = 10

Step-by-step explanation:

1) Expand the module as two separate equations:

x - 3 = 7

x - 3 = -7

2) Solve the equations:

x = 10

x = -4

=> x1 = -4; x2 = 10

5 0
3 years ago
A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us
amm1812

Answer:

Given:

Sham: n= 20,     x=0.44,   s=1.24,

Magnet:n= 20,  x =0.49,   s= 0.95

For Sham:

Sample size, n = 20

Sample mean = 0.44

Standard deviation = 1.24

For Magnet:

Sample size = 20

Sample mean = 0.49

Standard deviation = 0.95

The null and alternative hypotheses:

H0: s1²=s2²

H1: s1² ≠ s2²

a) To find the test statistics, use the formula:

\frac{s1^2}{s2^2}

\frac{1.24^2}{0.95^2} = \frac{1.5376}{0.9025} = 1.7037

Test statistics = 1.7037

b) P-value:

Sham: degrees of freedom = n - 1 = 20 - 1 = 19

Magnet: degrees of freedom = n - 1 = 20 - 1 = 19

The critical values:

[Za/2, df1, df2)], [(1 - Za/2), df1, df2]

f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]

f[0.025, 19, 19], f[0.975, 19, 19]

(2.526, 0.3958)

The rejection region:

Reject H0, if  F < 0.3958 or if F > 2.526

c) Conclusion:

Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.

There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets

3 0
3 years ago
Solve for v: -8(v - 6) + 7 ≤ -7(v + 1)
meriva

Answer:

V is greater than or equal to 62

4 0
3 years ago
Two ropes are attached to a large ballon in a parade. The people holding the ropes are 40 feet apart,and the angle between the t
tankabanditka [31]

Answer:

We'll use the Law of Sines:

Sine (C) / c = Sine (B) / b

Sine (86) / 40 = Sine (52) / b

0.99756 / 40 = 0.78801 / b

0.024939  = .78801 / b

b = .78801 / .024939

side b = 31.5974978949  feet

Sine (42) / a = Sine (86) / 40

(0.66913 / a) = 0.024939

a = .66913 / .024939

side a = 26.8306668271  feet

******************************************************

I forgot to include the graphic.  

Step-by-step explanation:

8 0
3 years ago
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