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ludmilkaskok [199]
4 years ago
6

): How many times longer is the diameter of a grain of sand than the diameter of the average cell in the human body? Show your w

ork.    Need help bad:(
Mathematics
1 answer:
Airida [17]4 years ago
4 0
<span>Approximately 25. Of the 5 grades of sand used in the United states, medium sand has particles ranging from 0.25 mm to 0.5 mm. For convenience, I'll use 0.5mm as the diameter of a grain of sand. Human cells range from a volume of 30 cubic micrometers (human sperm cell) up to 4 million micrometers (human egg cell). For the average human cell, I'll use an osteoblast with a volume of 4000 cubic micrometers or a diameter of 2x10^-5 meters. Now just take the diameter of a grain of sand and divide by the diameter of a human cell. 5 x 10^-4 / 2x10^-5 = 5/2 x 10^(-4 - -5) = 2.5x10^1 = 25 So the diameter of a grain of sand at 0.5 mm is approximately 25 times larger than that of a human cell at 0.02mm</span>
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Sue ran 7 miles more than Jill last week. Sue ran 11 miles. Which equation will tell you how many miles Jill ran?
Yuri [45]

Answer:

The number of miles Jill ran is the number of miles Sue ran (11) minus the number of miles Sue ran more than Jill (7).

So far, x=11-7.

Reorder the equation. Add 7 to both sides.

x + 7 = 11.

So, the correct equation is A.

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3 years ago
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Is 8/10 greater than 1/2
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32. Parallelogram ABCD has vertices A(0,0), B(2,4), and C(10,4). Find the coordinates of D.
goblinko [34]

Answer:

The fourth vertex is D(8, 0)

Step-by-step explanation:

Let A(0, 0), B(2, 4), and C(10, 4) be the three vertices of a parallelogram ABCD and let its fourth vertex be D(a, b).

Join AC and BD. Let AC and BD intersect at point O.

  • We have known that the diagonals of a parallelogram bisect each other.  

So, O would be the midpoint of AC as well as that of BD.

A\left(0,\:0\right)=\left(x_1,\:x_2\:\right)

C\left(10,\:4\right)=\left(x_2,\:x_2\:\right)

The midpoint of AC is:

\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x_1,\:y_1\right)=\left(0,\:0\right),\:\left(x_2,\:y_2\right)=\left(10,\:4\right)

=\left(\frac{10+0}{2},\:\frac{4+0}{2}\right)

=\left(5,\:2\right)

The midpoint of BD is:

=\left(\frac{a+2}{2},\:\frac{b+4}{2}\right)

so

∵  \frac{a+2}{2}=5

a+2=10

a=8

∵ \frac{b+4}{2}=2

b+4=4

b=0

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3 years ago
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