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Lera25 [3.4K]
4 years ago
6

Helppp hurryyyyy................-6 > x - 22

Mathematics
1 answer:
ahrayia [7]4 years ago
5 0
OK........

X < 16

H0P3 It H3LPS :)
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Solve for Y<br><br><br> -6x-2y+8
Mkey [24]

Step-by-step explanation:

-6x-2y+8

-6x -6x

÷-2 (-2y=-6x+8)

3x=-4

x= 3x

y= -4

y=-4-3x

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4 years ago
Select the correct answer.
Elena L [17]

Answer:

b because first u need to remove the parentheses then u disturbe

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3 years ago
Gerald notices that the bank of lockers outside his math classroom are numbered 511, 513, 515, ..., 575. Determine the number of
marysya [2.9K]

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33

Step-by-step explanation:

(575-511)/2 + 1 = 33

8 0
3 years ago
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Does x*x*x*x*x = 5x?<br> I'm not really sure so it would help.
hodyreva [135]

Answer:

Step-by-step explanation:

no ,x*x*x*x*x=x^5

x+x+x+x+x=5x

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6 0
3 years ago
Recall the equation for a circle with center ( h , k ) and radius r . At what point in the first quadrant does the line with equ
astraxan [27]

Answer:

The Point in the first quadrant is (\sqrt[2]{2.0268} ,6.559).

Step-by-step explanation:

Since

we know the general equation of the circle whose center is at (h,k) and radius is r that is

(x-h)^2+(y-k)^2 =r^2

we have given center is (0,3) and radius is r= 4

substituting in the general equation of the circle we get

x^2 +(y-3)^2 = 16

Now substituting the y= 2.5x + 3 in the above equation we get

x^2 +(2.5x + 3-3)^2 = 4^2

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here subtracting 16 from both sides  and also perform addition

we get

7.25x^2 = 16

dividing both sides by 7.25 we get

x^2 =2.2068

taking square root both sides we get

x= \frac{+}{-}\sqrt[2]{2.0268}

but we need positive value of x because both x and y are positive in the first quadrant

that is

x= \sqrt[2]{2.0268}

substituting this into the given equation of the line we get

y =  2.5(\sqrt[2]{2.0268})+3

y =  6.559

so the point in the first quadrant is (\sqrt[2]{2.0268},6.559)

that is required    

6 0
4 years ago
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