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Dmitrij [34]
3 years ago
10

What are its electron-pair and molecular geometries? What is the hybridization of the nitrogen atom? What orbitals on and overla

p to form bonds between these elements?
Electron-pair geometry =______________

Molecular geometry =___________

Hybridization = _________________

The bonds are formed by the overlap of the hybrid orbitals on nitrogen with the orbitals on____________- .
Chemistry
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer:

Electron-pair geometry: tetrahedral

Molecular geometry: trigonal pyramidal

Hybridization: sp³

sp³ - 4 p

Explanation:

There is some info missing. I think this is the original question.

<em>For NBr₃, What are its electron-pair and molecular geometries? What is the hybridization of the nitrogen atom? What orbitals on N and Br overlap to form bonds between these elements?</em>

<em>The N-Br bonds are formed by the overlap of the  ___ hybrid orbitals on nitrogen with ___ orbitals on Br.</em>

<em />

Nitrogen is a central atom surrounded by 4 electron domains. According to VESPR, the corresponding electron-pair geometry is tetrahedral.

Of these 4 electron domains, 3 represent covalent bonds with Br and 1 lone pair. According to VESPR, the corresponding molecular geometry is trigonal pyramidal.

In the nitrogen atom, 1 s orbital and 3 p orbitals hybridize to form 4 sp³ orbitals for each of the electron domains.

The N-Br bonds are formed by the overlap of the sp³ hybrid orbitals on nitrogen with 4p orbitals on Br.

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5 0
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Answer:

\boxed{\text{378 g}}

Explanation:

We must convert formula units of Zn(ClO₃)₂ to moles and then to grams of Zn(ClO₃)₂.

Step 1. Convert formula units to moles

\text{Moles of Zn(ClO$_{3}$)$_{2}$}\\\\= 9.80 \times10^{23}\text{ formula units Zn(ClO$_{3}$)$_{2}$} \times \dfrac{\text{1 mol Zn(ClO$_{3}$)$_{2}$}}{6.022 \times\ 10^{23} \text{ formula units Zn(ClO$_{3}$)$_{2}$}}\\\\= \text{1.627 mol Zn(ClO$_{3}$)$_{2}$}

Step 2. Convert moles to grams

\text{Mass of Zn(ClO$_{3}$)$_{2}$}\\\\= \text{1.627 mol Zn(ClO$_{3}$)$_{2}$} \times \dfrac{\text{232.29 g Zn(ClO$_{3}$)$_{2}$}}{\text{1 mol Zn(ClO$_{3}$)$_{2}$}}\\\\= \text{378 g Zn(ClO$_{3}$)$_{2}$}\\\\\text{The mass of Zn(ClO$_{3}$)$_{2}$ is } \boxed{\textbf{378 g}}

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Explanation:

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