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babunello [35]
3 years ago
14

How many grams are in 2.3 x 1024 formula units of KNO3?

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
5 0
<h2>Answer:</h2>

390 g KNO₃

<h2>General Formulas and Concepts:</h2><h3><u>Chemistry</u></h3>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3><u>Math</u></h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h2>Explanation:</h2>

<u>Step 1: Define</u>

2.3 × 10²⁴ formula units KNO₃

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g.mol

Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol

<u>Step 3: Convert</u>

<u />2.3 \cdot 10^{24} \ formula \ units \ KNO_3(\frac{1 \ mol \ KNO_3}{6.022 \cdot 10^{23} \ formula \ units \ KNO_3} )(\frac{101.11 \ g \ KNO_3}{1 \ mol \ KNO_3} ) = 386.172 g KNO₃

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules and round.</em>

386.172 g KNO₃ ≈ 390 g KNO₃

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