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3 years ago

NaOH(aq) + MgSO4(aq) →

Chemistry

1 answer:

Cerrena [4.2K]3 years ago

3 0

Answer:

if balanced reaction then 2 NaOH + MgSO4 → Mg(OH)2 + Na2SO4

Explanation:

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1.00 L of gas at a standard temperature and pressure is compressed to 473mL. What is the new pressure of the gas?

Nadusha1986 [10]

Answer:

The pressure of the gas is 2.11 atm.

Explanation:

From the given,

$V_{1}=1.00\,L$

$P_{1}=1\,atm$

$P_{2}=?$

$V_{2}=473\,ml=0.473\,L$

$P_{1}V_{1}=P_{2}V_{2}$

$(1)(1)=(0.473)(P_{2})$

$P_{2}=\frac{(1)(1)}{0.473}=2.11$

Therefore, The pressure of the gas is 2.11 atm.

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3 years ago

Study the scenario. The particles in a system are moving around very slowly. A few minutes later, the particles are moving, on a

Bogdan [553]

Answer:

The average kinetic energy of the system has increased as a result of the temperature increasing.

Explanation:

Assuming this is a gas based on the framing.

The molecules of a gas span a distribution of speeds, and the average kinetic energy of the molecules is directly proportional to the absolute temperature of the sample. KEavg is proportional to T.

This can be further studied until the Kinetic-Molecular Theory.

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2 years ago

Enter your answer in the provided box.

nexus9112 [7]

Answer:

V₂ = 50.93 L

Explanation:

Initial volume, $V_1=43.1\ L$

Initial temperature, $T_1=24^{\circ} C=24+273=297\ K$

Final temperature, $T_2=78^{\circ} C=78+273=351\ K$

We need to find the final volume of the gas. The relation between the volume and the temperature is given by :

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{43.1\times 351}{297}\\\\V_2=50.93\ L$

So, the final volume of the gas is 50.93 L.

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Answer:

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