5= Both parents must both be Heterozygous (Ee) because they have unattached earlobes but can still produce offsprings with attached earlobes because they still possess the recessive gene (e).
6=Punnett Square: (top right)-tt, (bottom right)-tt. Genotypes= Tt, Tt, tt, tt. Phenotypes= Roller(Tt), Roller(Tt), unable to roll(tt), unable to roll(tt).
Answer:
138.6 g of C₂HF₃O₂ have 38.9 g of O
Explanation:
Trifluoroacetic acid → C₂HF₃O₂
Molar mass = Mass of C . 2 + Mass of H + Mass of F . 3 + Mass of O .2
Molar mass = 12 . 2 + 1 . 1 + 19 . 3 + 16 . 2 = 114 g /mol
1 mol of C₂HF₃O₂ has:
2 moles of C
1 mol of H
3 moles of F
2 moles of O
If we state the relation in mass by g we say:
114 g of C₂HF₃O₂ have 24g of C, 1 g of H, 57 g of F and 32 g of O
Let's make a rule of three:
32 g of O are contained in 114 g of C₂HF₃O₂
38.9 g of O may be contained in (38.9 . 114) / 32 = 138.6 g
The answer is D hopefully it is correct
Answer: it can form a maximum of one bond
Explanation:
Answer:
hard outer skin to reduce loss of water
Explanation:
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