i used polynomial division.. i hope this helps :)
Answer:
6 games.
Step-by-step explanation:
Given that,
Monthly membership fee of store 1 is $7.5, but then the charge to rent a game is only $1.00
Another store has no membership fee, but that store charges $2.00 to rent a game.
Let there be n games needed to be rented each month for the total fees to be the same from either store.
Cost of first store = $7.50+$1.00n
Cost of another store = $2.00
If cost equals,
$7.50+$1.00n=$2
n=5.5
6
Hence, 6 games needed to be rented each month.
Answer:
She rewrote the problem without parentheses: x3+ 2x2 - x + x3 – 2x2 +6
Step-by-step explanation:
It looks like she didn't fully distribute the -
(x3 + 2x2 - x)-(-x3 + 2x2 + 6) :Original
x3+ 2x2 - x + x3 – 2x2 +6 :Changed
~
(x3 + 2x2 - x)-(-x3 + 2x2 + 6)
x3 + 2x2 - x + x3 - 2x2 - 6
x3 + x3 + 2x2 - 2x2 -x - 6
2x3-x-6
I hope this helps ^-^