Find the range for the given domain: {-2, -1, and 0} and the function is y= 3x^2

Mathematics

1 answer:

likoan [24]3 years ago

6 0

Answer:

{0, 3, 12}

Step-by-step explanation:

Put the domain values in the function and evaluate. The result is the range values.

y = 3{-2, -1, 0}^2 = 3{4, 1, 0} = {12, 3, 0}

For the given domain, the range is {0, 3, 12}.

_____

<em>Additional comment</em>

Neither the domain nor range values need to be put in any particular order. However, it is often convenient for them to be arranged from least to greatest.

You might be interested in

How to do geometry ex determining angle measures

stiks02 [169]

Answer:

To determine to measure of the unknown angle, be sure to use the total sum of 180°. If two angles are given, add them together and then subtract from 180°. If two angles are the same and unknown, subtract the known angle from 180° and then divide by 2.

6 0

3 years ago

Is .32903 greater than 0.59

leonid [27]

No, <span>.32903 is not greater than 0.59</span>

5 0

3 years ago

Read 2 more answers

A container in the shape of a pyramid has a rectangular base with dimensions of 5 inches by 15 inches. The height of the rectang

Rama09 [41]

Answer:

150

Step-by-step explanation:

1) the full volume of the given pyramide may be calculated according to the formula:

V=1/3 *Area_of_base*height;

V=1/3 *(5*15)*12=300 (in³).

2) the half of the calculated volume is:

300/2=150 (in³)

8 0

3 years ago

Read 2 more answers

A 6-foot tall man casts a shadow that is 12 feet long. What is the measure of the sun's angle of elevation? Enter your answer, r

Masteriza [31]

Answer:

$27^{\circ}$

Step-by-step explanation:

Let x represent the sun's angle of elevation.

We have been given that a 6-foot tall man casts a shadow that is 12 feet long.

Upon looking at our attachment we can see that man and his shadow forma a right triangle with respect to ground, where height of man is opposite side and his shadow is adjacent side.

Since tangent relates opposite side of a right triangle with adjacent, so we can set an equation as:

$\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}$