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juin [17]
3 years ago
10

How many hours is 7/10​

Mathematics
1 answer:
spin [16.1K]3 years ago
7 0

70% or 0.7

Hope this helps!

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There are 418 students at a school. Han estimates that they each drink about 5 glasses of water each day.
Sauron [17]

Answer:

Step-by-step explanation:

a) together, they all drink about 2,090 glasses of water in one day. (418 * 5 = 2,090).

b) 2,090 * 7 (7 days in 1 week) = They drink about 14,630 glasses of water in one week.

c) 14,630 * 4 (4 weeks in 1 month) = About 58,520 glasses of water in one month.

d) 1,000,000/58,520 ≈ 17. It would take all of the students about 17 months to drink 1,000,000 glasses of water.

Hope that helps!

6 0
2 years ago
1- AT OAKNOLL SCHOOL, 90 OUT OF 270 STUDENTS OWN COMPUTERS. WHAT PERCENT OF STUDENTS OF OAKNOLL SCHOOL DO NOT OWN COMPUTERS? ROU
V125BC [204]
1. 270÷90=3=30% have and 70% don't have a computer.
8 0
3 years ago
Read 2 more answers
What is the perimeter of this shape? Use numbers only.
aniked [119]

Answer:

30 m

Step-by-step explanation:

You simply add the lengths of all the sides. 3 m is not needed for this.

8 0
2 years ago
Read 2 more answers
Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle
Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x+3)^{2} +(y-4)^{2}=r^{2}

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

r=\sqrt{(2-4)^{2}+(-6+3)^{2}}

r=\sqrt{(-2)^{2}+(-3)^{2}}

r=\sqrt{13}\ units

The equation of the circle is equal to

(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}

(x+3)^{2} +(y-4)^{2}=13

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

(10+3)^{2} +(4-4)^{2}=13

(13)^{2} +(0)^{2}=13

169=13 -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x-1)^{2} +(y-3)^{2}=r^{2}

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

r=\sqrt{(6-3)^{2}+(2-1)^{2}}

r=\sqrt{(3)^{2}+(1)^{2}}

r=\sqrt{10}\ units

The equation of the circle is equal to

(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}

(x-1)^{2} +(y-3)^{2}=10

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

(11-1)^{2} +(5-3)^{2}=10

(10)^{2} +(2)^{2}=10

104=10 -----> is not true

therefore

The point is not on the circle

The statement is false

7 0
3 years ago
MATH HELP PLEASE DRAW,, GEOMETRY ;3
Sophie [7]

E(1,-4)  F(1,-6)  G(-3,-5)  H(-3,-3)

7 0
3 years ago
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