3 years ago

How can you solve quadratic equations in one variable?

Mathematics

1 answer:

ivolga24 [154]3 years ago

6 0

you can use formular method or factorisation but formular method is easy and convinient

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Find the length of the missing side. Give your answer in the simplest radical form.

taurus [48]

Answer:

x = $2\sqrt{5}$

Step-by-step explanation:

Use Pythagorean theorem,

Hypotenuse² = base² + altitude²

x² = (√8)² + 4²

= 8 + 16

= 20

x = √20 = $\sqrt{2*2*5} = 2\sqrt{5}$

x = $2\sqrt{5}$

6 0

3 years ago

Which polynomial is a difference of two squares? x2 − 16 x2 + 16 x2 − 8 x2 + 8

mart [117]

Difference means subtract so we can reduce the choices right away to first and third choices. of the only the first is the difference of squares, namely x² - 4²

8 0

3 years ago

Use the quadratic formula to find the solutions to the quadratic equation below x^2-6x-5=0

Sonja [21]

Answer:

$\large\boxed{x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}}$

Step-by-step explanation:

$x^2-6x-5=0\qquad\text{add 5 to both sides}\\\\x^2-6x=5\\\\x^2-2(x)(3)=5\qquad\text{add}\ 3^2\ \text{to both sides}\\\\x^2-2(x)(3)+3^2=5+3^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-3)^2=5+9\\\\(x-3)^2=14\to x-3=\pm\sqrt{14}\qquad\text{add 3 to both sides}\\\\x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}$

8 0

2 years ago

A decrease in the price of a particular product will result in Question 7 options: a decrease in the demand for that product. a

sattari [20]

The answers you could use are both the second and the forth. But mostly the fourth.

6 0

3 years ago

Read 2 more answers

What radical expression is not simplified?

rodikova [14]

B 2/10 is not simplified because you can divide each number by 2 reducing it to 1/5.

5 0

3 years ago