The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
x=-7
Step-by-step explanation:
add 4 to both sides. leaving you with x=-7
Answer:
Step-by-step explanation:
Area of the figure = Area of rectangle with dimensions 16 in and 4 in + Area of two right triangles with base (7 - 4 = 3) 3 in and height 8 in


The formula for area of triangle is -

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So, the area of first triangle =



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Area of second triangle =



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Area of second triangle - Area of first triangle


