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lakkis [162]
3 years ago
9

Mean,median,mode,and range of 4,8,6,2,0,3,7,5,8,2mean,median,mode,and range of 4,8,6,2,0,3,7,5,8,2.

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

Mean: 4.5

Median: 4.5

Mode: 8, 2, each appeared 2 times

Range: 8

------------------------------------------------------------------

Put the numbers in order: 0, 2, 2, 3, 4, 5, 6, 7, 8, 8

To find the mean you must add up all the numbers (0+2+2+3+4+5+6+7+8+8). then divide the total (45) to the total of numbers there are (10)

To find the range you must subtract 8-0 (or add 8+0) and get 8.

Finding the median essentially involves finding the value in a data sample that has a physical location between the rest of the numbers. Note that when calculating the median of a finite list of numbers, the order of the data samples is important.

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How do I find the domain range and function of the graph
Allisa [31]

Answer:

  D = {-3, -2, -1, 1, 4}

  R = {-5, -1, 0, 2}

Step-by-step explanation:

You have correctly described the process of finding the domain and range by the way you filled in the blanks at the top of the sheet.

__

The domain is the set of x-values of the points on the graph:

  D = {-3, -2, -1, 1, 4}

The range is the set of (unique) y-values of the points on the graph:

  R = {-5, -1, 0, 2}

3 0
1 year ago
The perimeter of a rectangle is 36m. If its length is increased by 1m and the width is increased by 2m, its area will increase b
maw [93]

Answer:

  80 m^2

Step-by-step explanation:

The given information lets you write two equations involving length (x) and width (y).

  • 2(x +y) = 36 . . . . the perimeter is 36 m
  • (x+1)(y+2) -xy = 30 . . . . increasing the length and width increases area

The second of these equations simplifies to another linear equation, giving a system of linear equations easily solved.

  xy +y +2x + 2 -xy = 30

  2x +y = 28 . . . . . . . subtract 2

Dividing the first equation by 2 gives

  x +y = 18

and subtracting this from the above equation gives ...

  (2x +y) -(x +y) = 28 -18

  x = 10

Then

  y = 18 -10 = 8

The area of the original rectangle is xy = 10·8 = 80 m^2.

4 0
3 years ago
What is the greatest common factor of 32 and 48
Bond [772]
Turn each number into the product of it's prime factors.

32=16x2=2x2x2x2x2=2^5

48=24*2=6x4x2=2x3x2x2x2

Pick the highest number that occurs. In this case it is 2. Now we have to see how many times it appears in both. It appears 5 times in 32 and 4 times in 48. 4 is the highest number of times it appears in the numbers so:

2^4=2x2x2x2=16

The Greatest Common Factor (GCF) of 32 and 48 is 16.
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3 years ago
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Leno4ka [110]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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