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ioda
3 years ago
6

A plant is 20 inches tall. If the plant grows 2h inches each week for the next 4 weeks, and h inches for each of the 2 weeks aft

er that, which expression shows the height of the plant in inches after 6 weeks? A) 20 + 10h B) 20 - 10h C) 20 - 2h D) 20 + h
Please give a simple and clear answer.
Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0

Answer:

Option A is correct

20+10h

Step-by-step explanation:

As per the statement:

A plant is 20 inches tall.

It is also given that:

If the plant grows 2h inches each week for the next 4 weeks,

⇒(2h) \cdot 4 = 8h

and

h inches for each of the 2 weeks .

⇒(h) \cdot 2 = 2h

Then,  every 2 weeks after that, another 2h.

⇒ in 6 weeks, a total of 10h inches height of the plant grows

We have to find the expression shows the height of the plant in inches after 6 weeks.

Initially, a plant is 20 inches tall.

in 6 week,  a total of 10h inches height of the plant grows

⇒the height of the plant in inches after 6 weeks = 20 + 10h

Therefore, the expression shows the height of the plant in inches after 6 weeks is, 20+ 10h

FromTheMoon [43]3 years ago
3 0
A) 20+10h

You know that you have 20 inches to start with, then it will grow 2h four times, or 8h total. Then it will grow h 2 times, or 2h. You add the 20, 8h, and 2h, to get 20+10h.

Hope this helps!
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Determine the number of possible triangles, ABC, that can be formed given A = 30°, a = 7, and b = 18.
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none

Step-by-step explanation:

We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.

According to the 'Law of Sines- Ambiguous Case', we have,

If a < b×sinA, then no triangle is possible.

If a = b×sinA, only one triangle is possible

If a > b×sinA, two triangles are possible.

So, we have,

b×sinA = 10 × sin30 = 10 × 0.5 = 5.

Now, as

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2 years ago
Find the surface area of the two following figures. Show all your work.
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First shape: 366 in^2

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2 years ago
Which pair of triangles is congruent?
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Step-by-step explanation:

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Plz plz help me so i can get a good grade
Levart [38]

Area of the figure = 806.5 in²

Solution:

Length of the rectangle = 16 in

Breadth of the rectangle = 9 in

Area of the rectangle = length × breadth

                                    = 16 × 9

Area of the rectangle = 144 in²

Base of the triangle = 31 in

Height of the triangle = 20 in

Area of the triangle = \frac{1}{2}bh

                                 $=\frac{1}{2}\times 31\times 20

Area of the triangle = 310 in²

Parallel sides of the trapezium = 16 in and 31 in

Height of the trapezium = 35 – 20 = 15 in

Area of the trapezium = \frac{1}{2}\times \text{Sum of the parallel sides}\times \text{Height}

                                     $=\frac{1}{2}\times {(16+31)}\times{15}

                                     $=\frac{1}{2}\times {47}\times{15}

Area of the trapezium = 352.5 in²

Area of the figure = Area of rectangle + Area of triangle + Area of trapezium

                              = 144 in² + 310 in² + 352.5 in²

Area of the figure = 806.5 in²

8 0
3 years ago
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