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Citrus2011 [14]
3 years ago
11

Of the 120 rooms in a hotel, 55% are single bed rooms, 30% are double bed rooms and the rest are deluxe rooms. How many deluxe r

ooms are there

Mathematics
1 answer:
Nat2105 [25]3 years ago
6 0
Hey there !

Check the attachment.
Hope it helps you :)

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17x+11y=17 rewrite in slope intercept form
liq [111]

Answer:

y=-\frac{17}{11}x+\frac{17}{11}

Step-by-step explanation:

Rewrite the equation into y=mx+b form by rearranging terms using inverse operations.

17x + 11y = 17             Subtract 17x from both sides.

-17x               -17x

---------------------------

        11y = 17 - 17x      Divide by 11 on both sides.

          y = 17/11 - 17/11 x

The slope intercept form is y=-\frac{17}{11}x+\frac{17}{11}.

6 0
3 years ago
Which expression represents”9 less than the product of 5 and a number n”?
Alika [10]

9 less means subtract

the product of 5 and the number n mea multiply 5 and n

D. 5n-9

6 0
3 years ago
Read 2 more answers
46 is the sum of 9 and Hector's savings. Use the variable h to represent Hector's savings
AURORKA [14]
H+9=46
it would be a decimal
7 0
3 years ago
i) Baraka bought ksh.20,000 worth of shares of a company each month. During the first three months, he bought the shares at a pr
Sladkaya [172]

The average price paid by him for the shares after 3 months is ksh. 163.33

<h3>Average</h3>

  • Total value of shares bought = ksh.20,000

  • Amount of shares bought in the first three months = ksh.120, ksh.160 and ksh.210

Average price paid for the shares after 3 months

= (120 + 160 + 210) / 3

= 490 / 3

= 163.333333333333

Approximately,

ksh. 163.33

Learn more about average:

brainly.com/question/20118982

#SPJ1

4 0
2 years ago
Find the area of the shaded region. Round your answer to the nearest tenth.
Alex
Check the picture below on the left-side.

we know the central angle of the "empty" area is 120°, however the legs coming from the center of the circle, namely the radius, are always 6, therefore the legs stemming from the 120° angle, are both 6, making that triangle an isosceles.

now, using the "inscribed angle" theorem, check the picture on the right-side, we know that the inscribed angle there, in red, is 30°, that means the intercepted arc is twice as much, thus 60°, and since arcs get their angle measurement from the central angle they're in, the central angle making up that arc is also 60°, as in the picture.

so, the shaded area is really just the area of that circle's "sector" with 60°, PLUS the area of the circle's "segment" with 120°.

\bf \textit{area of a sector of a circle}\\\\&#10;A_x=\cfrac{\theta \pi r^2}{360}\quad &#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;r=6\\&#10;\theta =60&#10;\end{cases}\implies A_x=\cfrac{60\cdot \pi \cdot 6^2}{360}\implies \boxed{A_x=6\pi} \\\\&#10;-------------------------------\\\\

\bf \textit{area of a segment of a circle}\\\\&#10;A_y=\cfrac{r^2}{2}\left[\cfrac{\pi \theta }{180}~-~sin(\theta )  \right]&#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;r=6\\&#10;\theta =120&#10;\end{cases}

\bf A_y=\cfrac{6^2}{2}\left[\cfrac{\pi\cdot 120 }{180}~-~sin(120^o )  \right]&#10;\\\\\\&#10;A_y=18\left[\cfrac{2\pi }{3}~-~\cfrac{\sqrt{3}}{2} \right]\implies \boxed{A_y=12\pi -9\sqrt{3}}\\\\&#10;-------------------------------\\\\&#10;\textit{shaded area}\qquad \stackrel{A_x}{6\pi }~~+~~\stackrel{A_y}{12\pi -9\sqrt{3}}\implies 18\pi -9\sqrt{3}

7 0
3 years ago
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