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jekas [21]
3 years ago
14

There are 12 candidates running for any of 6 distinct positions in a school's student council. In how many different ways could

the 6 positions be filled?
Mathematics
1 answer:
deff fn [24]3 years ago
7 0

Answer:

Ways = 665280\ ways

Step-by-step explanation:

Given

Candidates = 12

Positions = 6

Required

Determine the number of ways to fill the vacant position

The first position can be any of the 12 candidates;

The next candidate can be any of the remaining 11

The next candidate can be any of the remaining 10

The next candidate can be any of the remaining 9

The next candidate can be any of the remaining 8

The next candidate can be any of the remaining 7

So: we have;

Ways= 12 * 11 * 10 * 9 * 8 * 7

Ways = 665280\ ways

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\purple{\bigstar}\underline{\underline{\boldsymbol{ According\ to \ Question :- }}}

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\rule{200}2

<u>The </u><u>percentage</u><u> of</u><u> </u><u>children </u><u>=</u><u> </u><u>1</u><u>5</u><u>%</u><u> </u><u>:</u><u>-</u>

\sf\implies Number_{(children)}= 15\% \ of 161,000\\\\\sf\implies Number_{(children)}= \dfrac{15}{100}\times 161,000 \\\\\sf\implies \boxed{\pink{\frak {Number_{(children)}= 24150 }}}

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