All categories

3 years ago

Find all solutions to the equation. cos^2x + 2 cos x + 1 = 0

Mathematics

2 answers:

mixas84 [53]3 years ago

5 0

$\cos^2(x)+2\cos(x)+1=0\\\\ (\cos(x)+1)^2=0\\\\ \text{So:}\\\\ \cos(x)+1=0\\\\ \cos(x)=-1\\\\ \boxed{x=\pi+2k\pi},~k\in\mathbb{Z}$

Umnica [9.8K]3 years ago

5 0

Hope this helps you.

You might be interested in

How would you solve

harkovskaia [24]

4r^-3 * 2r^2 =

4*(2r^(-3+2))

= 4*2r^-1

= 4*2(1/r)

= 4*(2/r)

=8/r

4 0

3 years ago

Please help with this

Sloan [31]

Answer:

quick question for you to change in what way do you want to be a good day at work and I don't know how to share with you and I don't

6 0

3 years ago

Help on questions 11 and 15 Add and simplify if possible

Svetllana [295]

$\frac{16+x}{x^3}+\frac{7-4x}{x^3}=\frac{16+x+7-4x}{x^3}=\frac{23-3x}{x^3}\\\\======================================\\\\\frac{5}{t-1}+\frac{3}{t}=\frac{5t}{t(t-1)}+\frac{3(t-1)}{t(t-1)}=\frac{5t+3t-3}{t^2-t}=\frac{8t-3}{t^2-t}$

7 0

3 years ago

Read 2 more answers

The difference of the degrees of the polynomials p(x) = 3x2y2 + 5xy? - x6 and q(x) = 3x5 - 4x3 + 2 is

svet-max [94.6K]

Answer:

The difference of the degrees of the polynomials p (x) and q (x) is 1.

Step-by-step explanation:

A polynomial function is made up of two or more algebraic terms, such as p (x), p (x, y) or p (x, y, z) and so on.

The polynomial’s degree is the highest exponent or power of the variable in the polynomial function.

The polynomials provided are:

$p(x) = 3x^{2}y^{2} + 5xy - x^{6}\\\\q(x) = 3x^{5} - 4x^{3} + 2$

The degree of polynomial p (x) is:

$\text{deg}\ p (x)=6$

The degree of polynomial q (x) is:

$\text{deg}\ q (x)=5$

The difference of the degrees of the polynomials p (x) and q (x) is:

$\text{deg}\ p(x)-\text{deg}\ q(x)=6-5=1$

Thus, the difference of the degrees of the polynomials p (x) and q (x) is 1.

6 0

3 years ago

I have a question and I cant seem figure it out. It says( Triangle ABC is a right triangle. Angle B is the right angle, side A i

pychu [463]

Answer:

you need to draw a triangle of given dimensions

Step-by-step explanation:

if B is right angle triangle then you can assume that either AB or BC is base and other one is perpendicular. So that makes AC hypotenuse

so let's assume BC is base of 6 cm. so draw a base of 6 cm line , name it BC

then draw a 90 degree angle on B keeping BC as Base . now length of perpendicular would be 4.5 cm. this perpendicular would be AB

no join A and C . length of AC should be 7.5 cm. if it's not then something is wrong in given question.

8 0

3 years ago