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Serga [27]
3 years ago
14

The number of geese at a city park in the year 2015 was 132. The population is declining by 3 geese every two years. The populat

ion expressed as a sequence is
Pn=132−3/2n
Find P10. What does this number represent?
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
7 0

Answer:

Step-by-step explanation:

p10 would be 117 geese

132-3/2(10)

132-15

117

The number represents the population after 10 years

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12

Step-by-step explanation:

2 : 6  pencil : eraser

? : 36

36 divided 6 = 6

so to get to the unknown value u multiply 2 x 6

which equals 12

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En una tienda comercial anuncia descuentos sucecivos del 30% y 20% en todos los electrodomésticos, ¿Que descuento único equivale
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Three times a number plus 12 minus 5 times the same number is 22. What is the number?​
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Answer:3

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3 years ago
A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a potential cust
AlexFokin [52]

Answer:

(a) The probability the salesperson will make exactly two sales in a day is 0.1488.

(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(c) The percentage of days the salesperson does not makes a sale is 43.05%.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let <em>X</em> = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts <em>n</em> = 8 potential customers per day.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={8\choose x}0.10^{x}(1-0.10)^{8-x};\ x=0,1,2,3...

(a)

Compute the probability the salesperson will make exactly two sales in a day as follows:

P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488

Thus, the probability the salesperson will make exactly two sales in a day is 0.1488.

(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

E(X)=np=8\times 0.10=0.80

Thus, the expected number of sales per day is 0.80.

7 0
3 years ago
Line k is parallel to y= -2x - 1 and passes through the point (4,3). What is the y intercept of line k?
Schach [20]
Yk what all above you can’t go wrong with choosing all of the em tbh cuz u would get one of them righ
4 0
2 years ago
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