Answer:
The fourth term of the expansion is -220 * x^9 * y^3
Step-by-step explanation:
Question:
Find the fourth term in (x-y)^12
Solution:
Notation: "n choose k", or combination of k objects from n objects,
C(n,k) = n! / ( k! (n-k)! )
For example, C(12,4) = 12! / (4! 8!) = 495
Using the binomial expansion formula
(a+b)^n
= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n
For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is
C(n,3)a^(n-3)b^3
=C(12,3) * x^(12-3) * (-y)^(3)
= 220*x^9*(-y)^3
= -220 * x^9 * y^3
Answer:
67 1/2
Step-by-step explanation:
22 1/2*3
Answer: (a) $6,600
(b) $28,600
<u>Step-by-step explanation:</u>
Interest (I) = Principal (P) x rate (r) x time (t)
I = 22,000(0.06)(5)
= 6,600
Accrued (A) = Principal (P) + Interest (I)
A = 22,000 + 6,600
= 28,600
Answer:
14 Rainbow, 28 Swordtail, and 21 Molly. He can still have 7 more fish.
Step-by-step explanation:
Answer:
7 packs
Step-by-step explanation:
2.75p < 20
Divide both sides by 2.75
2.75p/2.75 < 20/2.76
Simplify
p = 7.27 (27 repeating)
Round
p = 7
