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2 years ago

A banner has a length of 10 feet and an area of 7 square feet. What is the width of the banner?

Mathematics

1 answer:

const2013 [10]2 years ago

6 0

Answer:

the width is 0.7 feet

Step-by-step explanation:

Well we know that area = length * width. We know both the area and length, but not the width. Let's substitute the area and length in this equation, and substitute x for the width.

7 = 10 * x, or 7 = 10x

Now, solve for the width, or x, by dividing both sides by 10.

7(/10) = 10x(/10)

7/10 = x

Simplify 7/10 = 0.7

So the width of the banner is is 0.7 ft!

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3 years ago

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

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Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

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$Area \approx 1149\ cm^2$

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3 years ago

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