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3 years ago

Th Write an explicit formula for an, the n term of the sequence 11, 9,7

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

3 0

Step-by-step explanation:

everything can be found in the picture above

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As an estimate we are told 5miles is 8km convert 68 km to miles ?

Alexxandr [17]

Answer:

42.5miles

Step-by-step explanation:

68÷8= 8.5

8.5×5= 42.5 miles

we use the numbers given to us because we are finding the estimate.

our estimate is correct because 68km= 42.3 miles

4 0

3 years ago

Read 2 more answers

Ricky race $640 in a charity walk last year this year he raised 15% more than he raised last year how much money did Ricky raise

Mashutka [201]

He raised $736.

One way is to multiply 640 x .15 = 96
Add 96 + 640 = 736

8 0

3 years ago

If I have a 92,70,41 what's my average grade?

Alexandra [31]

Answer: Around 67%

Step-by-step explanation:

92+70+41=203

203/3=67 2/3

Around 67%

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3 years ago

Read 2 more answers

two bicycle riders start from the same point and ride in opposite directions. one rider is moving twice as the other. in 3 hours

Likurg_2 [28]

Step-by-step explanation:

let X = speed of slow bicycle rider

2x=speed of fast bicycle rider

3(x+2x)=72

X=8mph(slowest bicycle rider)

2x=16mph(fastest bicycle rider)

5 0

3 years ago

In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8;

Fiesta28 [93]

We have to find the expansion of $(3a+4b)^{8}$

We will use binomial expansion to expand the given expression, which states that the expression $(a+b)^{n}$ is expanded as :

$(a+b)^{n}=^{n}C_{0}a^{n}+^{n}C_{1}a^{n-1}b+^{n}C_{2}a^{n-2}b^{2}+........^{n}C_{n}b^{n}$

Now expanding $(3a+4b)^{8}$ we get,

$(3a+4b)^{8}=^{8}C_{0}(3a)^{8}+^{8}C_{1}(3a)^{7}(4b)+^{8}C_{2}(3a)^{6}(4b)^{2}+^{8}C_{3}(3a)^{5}(4b)^{3}+^{8}C_{4}(3a)^{4}(4b)^{4}+^{8}C_{5}(3a)^{3}(4b)^{5}+^{8}C_{6}(3a)^{2}(4b)^{6}+^{8}C_{7}(3a)(4b)^{7}+^{8}C_{8}(4b)^{8}$

$(3a+4b)^{8}=^{8}C_{0}(3)^{8}a^{8}+^{8}C_{1}(3)^{7}(4)(a^{7}b)+^{8}C_{2}(3)^{6}(4)^{2}(a^{6}b^{2})+^{8}C_{3}(3)^{5}(4)^{3}(a^{5}b^{3})+^{8}C_{4}(3)^{4}(4)^{4}(a^{4}b^{4})+^{8}C_{5}(3)^{3}(4)^{5}(a^{3}b^{5})+^{8}C_{6}(3)^{2}(4)^{6}(a^{2}b^{6})+^{8}C_{7}(3)(4)^{7}(ab^{7})+^{8}C_{8}(4)^{8}(b^{8})$

So, the variables are $a^{5}b^{3}$ , $b^{8}$ , $a^{4}b^{4}$ , $a^{8} , [tex] ab^{7}$

5 0

3 years ago