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Arada [10]
3 years ago
5

A streamer goes downstream from point A to B in 9hrs .from B to A ,upstream it takes 10h .if the speed is 1km/hr , what will be

the speed of the streamer in still water ? also find distance between the point A to B
Mathematics
1 answer:
Snezhnost [94]3 years ago
8 0

Answer:

The distance  between the point A to B 180 kilometres.

The streamer speed in still water is 19 kmph

Step-by-step explanation:

Let be the distance between the ports (in kilometres) be d

let  the streamer speed in still water be s

Then speed equation for moving downstream

\frac{d}{9} =  s + 1------------------------(1)

The speed equation for moving upstream

\frac{d}{10} =  s - 1-------------------------(2)

On solving (1) and (2)

\frac{d}{9} -\frac{d}{10} =  2

\frac{10d -9d}{90} = 2

\frac{d}{90} = 2

d = 90 \times 2

d =  180

Thus the distance  between the point A to B 180 kilometres.

Now from equation 1

\frac{180}{9} =  s + 1

20 = s + 1

20 -1 = s

19 = s

The streamer speed in still water is 19 kmph

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Answer: The correct answer is option B: There are between 15 and 20 green pieces in all 5 packages

Step-by-step explanation: The most important factor has been given which is, "Which statement about the candy pieces in the remaining packages is best supported by this information."

The information given is such that, the first package she opened had 4 green pieces and on this basis we can safely assume that all other packages have 4 green pieces as well. The second package had 3 green pieces and this based on this too we can safely assume that all other packages had 3 green pieces. Hence, all 5 packages can either have a total of 4 x 5 green candies which equals a total of 20 green pieces or, all 5 packages can have a total of 3 x 5 green candies which equals a total of 15 green pieces.

So according to Suzi's experiment, there are between 15 and 20 green pieces in all 5 packages.

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3 years ago
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Answer:

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Step-by-step explanation:

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4. A random variable X has a mean of 10 and a standard deviation of 3. If 2 is added to each value of X, what will the new mean
Ede4ka [16]

Adding 2 to each value of the random variable X makes a new random variable X+2. Its mean would be

E[X+2]=E[X]+E[2]=E[X]+2

since expectation is linear, and the expected value of a constant is that constant. E[X] is the mean of X, so the new mean would be

E[X+2]=10+2=12

The variance of a random variable X is

V[X]=E[X^2]-E[X]^2

so the variance of X+2 would be

V[X+2]=E[(X+2)^2]-E[X+2]^2

We already know E[X+2]=12, so simplifying above, we get

V[X+2]=E[X^2+4X+4]-12^2

V[X+2]=E[X^2]+4E[X]+4-12^2

V[X+2]=(V[X]+E[X]^2)+4E[X]-140

Standard deviation is the square root of variance, so V[X]=3^2=9.

\implies V[X+2]=(9+10^2)+4(10)-140=9

so the standard deviation remains unchanged at 3.

NB: More generally, the variance of aX+b for a,b\in\mathbb R is

V[aX+b]=a^2V[X]+b^2V[1]

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