Answer: 0.6521
Step-by-step explanation:
According to the Binomial distribution , the provability of getting x successes in n trials is given by :-
, where p=probability of getting success in each trial.
Let x denotes the number of defective products.
here , n=7 and p =0.14
Then, the probability that among 7 randomly selected products, at least one of them is defective= P(X ≥ 1) =1- P(X<1)
= 1- P(X=0)
Hence, the probability that among 7 randomly selected products, at least one of them is defective is 0.6521 .