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3 years ago

11

A ball is drawn at random from a box containing 6 red balls,4 white balls and 5 blue balls. what is the probability of picking a

blue balls

1 answer:

lions [1.4K]3 years ago

7 0

Answer:

1/3

Step-by-step explanation:

6+4+5=15 total number of balls

blue = 5 balls

5/total number = 5/15

=1/3

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12/5 rename the fractions as mixed numbers

Alex_Xolod [135]

Answer:

2 2/5

Step-by-step explanation:

12 can go into 5 2 times with a left over of two, so it would be 2 which is 10 and a left over of two. The denominator stays the same. So it would be 2 2/5.

5 0

2 years ago

Please help!! Due really soon!

Alisiya [41]

9514 1404 393

Answer:

f(x) = 6x +1

Step-by-step explanation:

Differences in x-values (first row) are 1, 1, 1.

Differences in y-values (second row) are 6, 6, 6.

The constant ratio of differences (6/1) tells you the function is linear, and has a slope of m = 6/1 = 6.

Using the first point in the form ...

y = mx + b

we have ...

y = 6x + b

7 = 6·1 + b . . . . (x, y) = (1, 7)

1 = b . . . . . . subtract 6

Then the equation can be written ...

y = 6x +1

In functional form, this is ...

f(x) = 6x +1

4 0

3 years ago

NEED ANSWER ASAP PLEASE HELP

Artyom0805 [142]

Step-by-step explanation:

the answer is C I'm 100% sure of it

3 0

3 years ago

11. What is the reciprocal of 6/5?<br> OA. 12/20<br> OB.11/5<br> OC.1<br> OD.576

Elanso [62]

Answer: The answer is D, 5/6.

Step-by-step explanation: The reciprocal of a fraction is that fraction but the numerator and denominater swapped places.

3 0

3 years ago

Read 2 more answers

The differential equation in Example 3 of Section 2.1 is a well-known population model. Suppose the DE is changed to dP dt = P(a

LuckyWell [14K]

Answer:

Decreases

Step-by-step explanation:

We need to determine the integral of the DE;

$dP/dt=P(aP-b)$

$dP=P(aP-b)dt$

$1/(dP^2-bP)dP=dt$

We can solve this by integration by parts on the left side. We expand the fraction 1/P²:

$1/(d-b/P)\cdot{P^2} dP$

let

$u=d-b/P$

$du/dP=b/P^2$

$dP=$ $\int\limits {P^2/b} \, du$

$P=lnu/b$

Substitute u in:

$P=ln(d-b/P)/b$

Therefore the equation is:

$ln(d-b/P)/b=t$

We simplify:

$d-b/P=e^b^t$

$P=b/(d-e^b^t)$

As t increases to infinity P will decrease

6 0

3 years ago