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Vadim26 [7]
3 years ago
15

What are the zeros of the function? f(b) =b ^2 − 16b + 64

Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

b = 8 and b = 8

Step-by-step explanation:

f(b) =b² − 16b + 64 is set equal to zero and solved for b:

f(b) =b² − 16b + 64 = 0

This quadratic can be factored, as follows:  f(b) = (b - 8)(b - 8) = (b - 8)² = 0

There are two real, equal zeros:  b = 8 and b = 8.

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Answer:

x = -5/7

Step-by-step explanation:

8               1

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Using cross products

8 (x+1) = 1 (x+3)

Distribute

8x+8 = x+3

Subtract x from each side

8x-x +8 = x-x+3

7x+8 =3

Subtract 8 from each side

7x +8-8 =3-8

7x = -5

Divide each side by 7

7x/7 = -5/7

x = -5/7

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I hope this helps

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