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Radda [10]
3 years ago
8

What introduction proof is FH=FG=GH

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

What grade are you in I might know it

You might be interested in
Given Angle 1 =xº and angle 2 = (x +50)°.<br> Find the value of x. Then find angle 1 and 2
Elis [28]

Answer:

x=65

Angle 1=65

Angle 2=115

Step-by-step explanation:

We know that angle 1 + angle 2 = 180. Writing it in terms of x, we get x + (x + 50)= 180. Then you have 2x+50=180. Subtracting 50 from both sides gives you 2x=130. Dividing both sides by 2, you get x=65. Angle 1 is 65 degrees. 180-65=115.

6 0
3 years ago
What is the distance between the points R (5,7) and S (-2,3) 1: 25 2:33 3:55 or 4:65
Shtirlitz [24]
d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}
d = \sqrt{(-2 - 5)^{2} + (3 - 7)^{2}}
d = \sqrt{(-7)^{2} + (-4)^{2}}
d = \sqrt{49 + 16}
d = \sqrt{65}

The answer is 4, √(65).
6 0
3 years ago
HELPPPPPPPPP ME PLEASE
My name is Ann [436]
Answer: -8i
Explanation: Simplify the real and imaginary parts of that expression step by step to be left with -8i

Hope this helps!
3 0
3 years ago
A large high school has 3,000 students.
Leno4ka [110]

Answer:

120 students don't have social media accounts

Step-by-step explanation:

Whether the sample is representative:

Estimate: \frac{3}{75} (3000)=\frac{9000}{75} =120

Hope this helps

7 0
2 years ago
Which term describes how to determine if a relation given in a table is a function
True [87]

Answer:

A. If none of the output values are repeated, the relation is a function

Step-by-step explanation:

The reason why A is correct stems from the concept of the vertical line test. If each x-value has their own respective output (y-value), then the relation is a function.

Choice B just states that if none of the x-values are repeated. then the relation is a function. This is not correct because it doesnt follow the vertical line test, which analyzes if any y-values are being repeated

Choice C and D doesnt have any correlation with the vertical line test because an x-value doesnt have to equal a y-value to make the relation a function. Vice versa for any y value being equal to any x-value.

5 0
3 years ago
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