Answer:
C ≈ 22.1°
Step-by-step explanation:
The law of cosines formula is given. Solving it for C, we find ...
C = arccos((a^2 +b^2 -c^2)/(2ab))
where a and b are the sides adjacent to the angle.
Then we have ...
C = arccos((14^2 +19^2 -8^2)/(2·14·19)) = arccos(493/532)
C ≈ 22.1°
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If you have a fair number of these to do, a spreadsheet is a useful tool. There are also triangle solver apps on the web or your local smart platform that will do this, too.
It may or may not be 2 but I for a person dont know
Answer:
0.40g MgO - 0.24g Mg = 0.16g O
Step-by-step explanation:
Rhombuses are a type of parallelogram, which means their opposite sides are always parallel, and their opposite angles are always equal. A square<span> is the only type of </span>rhombus<span> where all four angles are equal, and the only </span>rhombus<span> that also meets the definition of a rectangle (all angles are 90 degrees).</span>
You would solve this by determining how many numbers from 1-10 can be multiples of 5. That's obviously 5 and 10. So that's 2/10 or reduced to 1/5. Now the second question you have to find how many numbers from 1-10 are prime. Prime is a number that can only be divided by 1 and itself. So that would leave you with 1, 3, 5, 7. I think where the trick comes into play is if you drew a 5 or 10 the first time, then you didn't place those cards back in the box, you couldn't draw them again. So the answer would 4/10 or 2/5 if you could draw the 5 again. Or I supposed if you had drew the 10 the first time and not the 5. I assume however, they want you to exclude 5 and 10 because it was part of the first section of this equation. So that would mean only 1, 3, and 7 or 3/10.
