So the trick I was taught to use was PEMDAS which stands for Parenthesis, Exponents, Multiplication, Division, Addition, and Subtraction. You solve the parenthesis first, followed by exponents if there are any. Multiplication and division are equal. So if there's multiplication and division in the problem, you solve the one closest to the left or start of the equation first. The same rules apply for addition and subtraction. They are both equal so you solve the first one first, even if the subtraction is before the addition.
Answer:
tangent theta = 12/5,
cosecant theta = 13/12
secant theta = 13/5
Cotangent theta = 5/12
Step-by-step explanation:
Given sine theta= 12/13, cosine theta= 5/13.
According to SOH CAH TOA
Sintheta = Opposite/Hypotenuse = 12/13
Cosine theta = Adjacent/Hypotenuse = 5/13
Opposite = 12, Adjacent = 5, Hypotenuse = 13
Tan theta = Opposite/Adjacent = 12/5.
cosecant theta = 1/sintheta = 1/{12/13}
cosecant theta = 13/12
secant theta = 1/cos theta = 1/{5/13}
Secant theta = 13/5.
Cotangent theta = 1/tan theta = 1/{12/5} = 5/12
Answer: I got it
Step-by-step explanation:
SA = bh + (s1 + s2 + s3)H
Answer:
Step-by-step explanation:
We begin with the fact that P + Q + R = 25300. Now we need to state all of those variables in terms of just one, since we can't have more than one unknown in an equation.
If Q is half as much as P, then
Q = 1/2 P
If R has twice as much as Q, then
R = 2Q, but since Q = 1/2P then
R = 2(1/2P) which is just P. So
R = P and the equation then becomes
P + 1/2P + P = 25300 and
R also is 10120.
Since Q is half of that,
Q = 5060
