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Marat540 [252]
3 years ago
14

If P = 0.50, which is the best conclusion? a) H0 is definitely false. b) H0 is definitely true. c) There is a 50% probability th

at H0 is true. d) H0 is plausible, and H1 is false. e) Both H0 and H1 are plausible.
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
3 0

Answer: option A

Step-by-step explanation: We can only make a conclusion regarding this question by picking a level of significance.

Hence I will assume a 5% level of significance, that's α = 0.05.

If p > α, it simply means that we have a high chance of committing a type 1 error (because α is the probability of committing a type 1 error), hence we reject the null hypothesis meaning it is wrong.

If p < α, it means that we have a very low chance of committing a type 1 error hence we accept the null hypothesis because it is right.

Note even if we decide to try any reasonable value of α, we will come to the same conclusion made above.

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Carolyn has $2.55 in her purse in nickels and dimes. The number of nickels is nine less than three times the number of dimes. Fi
Flauer [41]

Hi, the answer is ;

Answer:

12 dimes and 27 nickels

Step-by-step explanation:

.05N + .1d = 2.55

N= 3d - 9

0.05 (3d-9) + 0.1d = 2.55

0.15d - 0.45 + 0.1d = 2.55

0.25d = 2.55 + 0.45

0.25d = 3

D = 12

N = 3 (12) - 9

N = 36 - 9

N = 27

5 0
4 years ago
Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2
inna [77]
(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

6 x^{6}/3x = 2 x^{5} \\  \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\

We repeat previous steps until we run out of numbers:
3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2
\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )
6 0
3 years ago
Factor 2x^2-4x-30 completely
Elza [17]
2x² - 4x - 30
2(x²) - 2(4x) - 2(15)
2(x² - 4x - 15)
4 0
3 years ago
Eric and Carly each made a bowl of punch. Carly used 5 times as much lemonade as Eric did. If Eric used 1/4 of a
Viktor [21]

Answer:

carly used 1 1/4 cups of lemonade

Step-by-step explanation:

I think that is simplified

8 0
3 years ago
Create two whole number division problems
AlekseyPX
98 divided by 2 equals 49 55 divided by 5 equals 11
3 0
4 years ago
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