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Snezhnost [94]
2 years ago
12

Solve the given equation. State the number and type of roots. x² + 3x- 4

Mathematics
2 answers:
Rasek [7]2 years ago
5 0

Answer:(x+4)*(X-1)

Step-by-step explanation:

Into two binomial ( x + 4) x ( x -1)

Explanation:

The equation in the

A

x

2

+

B

x

+

C

The C is negative which indicates that one binomial will be negative and one binomial will be positive.

The B is positive which indicates that the positive binomial will be larger than the negative binomial

The B is +3 which tells that the difference in the two factors is 3

so

(x+4)*(X-1)

sesenic [268]2 years ago
4 0

Answer:

x=1, x=-4

Two distinct real roots

Step-by-step explanation:

x² + 3x- 4 = (x - 1)(x + 4)

x=1, x=-4

Two distinct real roots

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Answer:

I believe the correct answer is D

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2 years ago
Sound policy requires that a certain number of trees be planted for every tree that is cut down for example of 8 trees are cut d
Nimfa-mama [501]

Answer:

30 trees

Step-by-step explanation:

Given the policy:

8 trees are cut down 48 trees will be planted

If homeowner is going to cut down five trees on his property how many trees will be planted

Since :

8 trees cut down = 48 planted

5 trees cut down = X

Cross multiply :

8 * X = 48 * 5

8X = 240

X = 240/8

X = 30

Hence, 30 trees will need to be planted

4 0
3 years ago
Solve the following:<br> a.) X^2 - 2x – 24 = 0<br><br> b.) x^2 - 11x + 18 =0
wolverine [178]

Answer:

The answer for the first equation is,

X = 6, -4

The answer for second equation is,

X = 9,2

7 0
2 years ago
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How do you subtract<br> -6 - (-7)? <br> Can you explain it step by step too? Thanks!
djverab [1.8K]
\bf -6-(-7)\implies -6-1(-7)\implies -6-1\cdot -7\implies -6+(-1\cdot -7)&#10;\\\\\\&#10;-6+(+7)\implies -6+7\implies 1
3 0
3 years ago
Which second-degree polynomial function has a leading coefficient of –1 and root 5 with multiplicity 2?
PIT_PIT [208]
A second degree polynomial function has the general form:

                  \displaystyle{f(x)=ax^2+bx+c, where a\neq0.

The leading coefficient is a, so we have a=-1.

5 is a double root means that :

i) f(5)=0,
ii) the discriminant D is 0, where D=b^2-4ac.

Substituting x=5, we have

                                        f(5)=a(5)^2+b(5)+c,

and since f(5)=0, and a is -1 we have:

                                          0=-25+5b+c
thus c=25-5b.


By ii) \displaystyle{b^2-4ac=0.

Substituting a with -1 and c with 25-5b we have:
                                     
          \displaystyle{b^2-4ac=0
          \displaystyle{b^2-4(-1)(25-5b)=0
          \displaystyle{b^2+4(25-5b)=0
          \displaystyle{b^2-20b+100=0
          \displaystyle{(b-10)^2=0
          \displaystyle{b=10 


Finally we find c: c=25-5b=25-50=-25

Thus the function is        \displaystyle{f(x)=-x^2+10x-25


Remark: It is also possible to solve the problem by considering the form

f(x)=-1(x-5)^2 directly.

In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is f(x)=a(x-r)^2
5 0
2 years ago
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