Step-by-step explanation: look so if you have
shcool A its 8v+4b=12
and
School B: 12v+4b= 16
since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.
You should find part of the process to be
12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.
Answer -4
For both of the contests, the variable is the number of competitors which we can set as x.
Consequently, the equation should be 5.50x+34.60=4.25x+64.60
5.50x=4.25x+30
1.25x=30
x=24
The fee of the contests is the same when there are 24 competitors
Answer:
- 1y6
- 6x6y
- 1x6
- 4yx8
- a6b6
Step-by-step explanation:
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