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3 years ago

What is 10 times as much as 700?

Mathematics

2 answers:

Stels [109]3 years ago

8 0

7000 because 10 groups of 700 equals 7000

Hunter-Best [27]3 years ago

3 0

7,000 is your answer

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Factor this polynomial completely x2 + 3x – 18 A. (x-2)(x + 9) B. (x+3)(x-6) оо C. (x - 3)(x+6) D. (x - 3)(x-6)

Umnica [9.8K]

Answer:

C. $(x-3)(x+6)$

Step-by-step explanation:

I think the equation meant $x^2+3x-18$ ?

Anyways, to factor these kinds of quadratic, keep into consideration:

$ax^2+bx+c=(x+w)(x+v)$

ONLY if:

$w+v=b\\wv=c$

Start off by finding factors of c, which in this case, -18:

±(1, 2, 3, 6, 9, 18)

If one of the numbers is negative then the other number must be positive.

Find which two factors will sum up to b, which in this case, is 3.

$1+(-18)\neq 3\\2+(-9)\neq 3\\3+(-6)\neq 3\\6+(-3)=3\\9+(-2)\neq 3\\18+(-1)\neq 3\\$

The only two factors that work are 6 and -3.

Replace them into the factored form:

$(x+w)(x+v)\\(x+6)(x-3)\\(x-3)(x+6)$

3 0

2 years ago

Read 2 more answers

What is the surface area of the figure 8" 8" 12"

fgiga [73]

First, find the surface area of the bigger sides (there are 4 of them so what you get for one you will multiply by 4)

12 x 8 = 96

96 x 4 = 384

Then find the surface area of the smaller sides ( there are two small sides so multiply your answer by two)

8 x 8 = 64

64 x 2 =128

Then add both together

128 +384 = 512

Hope this helps :)

3 0

2 years ago

Prove the identity secxcscx(tanx+cotx)=2+tan^2x+cot^2x

svetlana [45]

Hello,

$sec(x)= \dfrac{1}{cos(x)} \\

cosec(x)= \dfrac{1}{sin(x)} \\

sec(x)*cosec(x)*(tg(x)+cotg(x))=\dfrac{1}{cos(x)}* \dfrac{1}{sin(x)}*( \frac{sin(x)}{cos(x)} +\frac{cos(x)}{sin(x)})\\

= \dfrac{sin^2(x)+cos^2(x)}{sin^2x*cos^2x} \\

= \dfrac{1}{sin^2x*cos^2x} \\

$
==============================================================
$2+tg^2(x)+cotg^2(x)=2+ \dfrac{sin^2x}{cos^2x} + \dfrac{cos^2x}{sin^2x} \\

=2+ \dfrac{sin^4x+cos^4x}{sin^2x*cos^2x} \\

=\dfrac{2*sin^2x*cos^2x+sin^4x+cos^4x}{sin^2x*cos^2x} \\

= \dfrac{(sin^2x+cos^2x)^2}{sin^2x*cos^2x}} \\

= \dfrac{1}{sin^2x*cos^2x}} 
$

8 0

3 years ago

Read 2 more answers

A ray bisects an obtuse angle into two congruent angles. what type of angles are these two congruent angles?

LenaWriter [7]

Angle bisector? I'm not sure sorry

6 0

3 years ago

Write 796.384 in expanded form

Korvikt [17]

700+90+6+0.3+0.08+0.004

3 0

3 years ago