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3 years ago

PLEASE HELP ME ITS DUEEE TODAYY!!!!!!!!!

Mathematics

1 answer:

vredina [299]3 years ago

7 0

height =h=16inch

Answer:

volume of cuboid =l×b×h

3840in³=20×12×h

h=3840/240=16inch

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Take 39/50 simplify into a fraction

Nat2105 [25]

Answer:

This fraction is in the simplest form already.

Step-by-step explanation:

This fraction is in the simplest form already. Here is why.

Result in decimals: 0.78

6 0

3 years ago

Find the ratio of (2,-5) and (7,-5) .

Bezzdna [24]

Answer:

1:-3, 1:2

Step-by-step explanation:

6 0

4 years ago

A coin is tossed 13 times.

Serga [27]

Answer:

a) 2¹³

b) 0.0873

c) 0.9983

d) 0.9538

Step-by-step explanation:

a) How many different outcomes are possible?

For every toss, there are two possible outcomes (heads or tails), so if we toss the coin 13 times the total of outcomes possible is 2¹³

b) What is the probability of getting exactly 4 heads?

The definition of probability is an event is: number of favourable events/ number of total events.

When we have two possible outcomes p, q and we repeat the experiment multiple times, we apply the Binomial distribution, in this distribution the probability of getting exactly k successes in n trials is given by

$P(X=k) =nCk (p^{k} )(1-p)^{n-k}$ where p represents the probability of success. nCk refers to the combinations of k elements out of n elements.

So we have to know how many different ways we can get exactly 4 heads.

let's name p = probability of getting heads = 0.5

1 -p = probability of getting tails = 0.5

We are going to toss the coin 13 different times and we want to get heads 4 times and tails 9 times.

So, by the Binomial Distribution we would have:

P(X=4) = 13C4 (0.5)⁴(0.5)⁹ = 715 (0.5)¹³ = 0.0873

Thus, the probability of getting exactly 4 heads is 0.0873.

c) What is the probability of getting at least 2 heads?

We are going to use the same binomial distribution but now we need at least to heads, this can be written as <u>1 - (P(X=0) + P(X=1))</u>

P(X=0) + P(X=1) = 13C0 (0.5)⁰(0.5)¹³ + 13C1 (0.5)¹(0.5)¹² = 0.0001220703125 + 0.0015869140625 = 0.001708984375

1 - 0.001708984375 = 0.998291015625

The probability of getting at least 2 heads is 0.9983

d) What is the probability of getting at most 9 heads?

We are going to use the same binomial distribution but now we need at most 9 heads. This can be written as <u>1 - (P(X=10) + P(X = 11) + P(X=12) + P(X=13))</u>

1 - (P(X=10) + P(X = 11) + P(X=12) + P(X=13)) =1 -(13C10(0.5)¹⁰(0.5)³ + 13C11(0.5)¹¹(0.5)²+ 13C12(0.5)¹²(0.5)¹ + 13C13(0.5)¹³(0.5)⁰) = 0.95385742188

The probability of getting at most 9 heads is 0.9538

6 0

3 years ago

Q1- Write 46 821 correct to the nearest 100

noname [10]

Answer:

46800

Step-by-step explanation:

46821 nearest 100s

look for the tens it is less than 5 so its 800 and the numbers written before the 100s would remain the same

8 0