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____ [38]
3 years ago
10

I need help with 34 it’s exponents

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

\frac{x^6}{216y^9}

Step-by-step explanation:

I'm gonna assume your assignment is to rewrite without negative exponents?

(6x^{-2}y^3)^{-3}

multiply the exponent into the parentheses, (a^{b} )^c = a^{bc}

(6x^{-2}y^3)^{-3} = 6^{-3} x^6y^{-9}

now move the negative exponents "downstairs"

6^{-3} x^6y^{-9} = \frac{x^6}{6^3*y^9}

negative exponents in denominator move up, in numerator move down

simplifying now

\frac{x^6}{6^3*y^9} = \frac{x^6}{216y^9}

the other way to do this is to move the entire inside down, then multiplying the exponent, like this

(6x^{-2}y^3)^{-3}=\frac{1}{(6x^{-2}y^3)^{3}} =\frac{1}{6^3*x^{-6}y^9}

then move things up and down

both ways will get you the same answer

Alchen [17]3 years ago
5 0

Answer:

nnalbn sjxNdcsfve

Step-by-step explanation:

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Solve for x. 4−(2x+4)=5
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4-(2x+4)=5\\-2x-4=1\\-2x=5\\x=-2.5

Put it back into the equation,

4-(2x+4)=5\\4-(2(-2.5)+4)=5\\4-(-5+4)=5\\4-(-1)=5\\5=5

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3 years ago
An automobile engineer is redesigning a conical chamber that was originally specified to be 12 inches long with a circular base
kirill115 [55]

Answer:

the original volume is lesser than the new volume by 242.47 in³

Step-by-step explanation:

Volume of a cone is;

V = ⅓πr²h

Where;

r is radius

h is height

For the original chamber;

r = 5.7/2 = 2.85 inches

h = 12 inches

Volume of this original chamber is;

V_orig = ⅓ × π × 2.85² × 12

V_orig = 102.02 in³

In the new design, the chamber is scaled by a factor of 1.5.

Thus;

r_new = 2.85 × 1.5 = 4.275 inches

h_new = 12 × 1.5 = 18 inches

V_new = ⅓ × π × 4.275² × 18

V_new = 344.49 inch³

V_new - V_orig = 344.49 - 102.02 =

Thus, the original volume is lesser than the new volume by 242.47 in³

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The bakers at healthy BAKERY can make 360 bagels in 10 hours. how many bagels can they bake in 13 hours? what was that rate per
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