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____ [38]
3 years ago
10

I need help with 34 it’s exponents

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

\frac{x^6}{216y^9}

Step-by-step explanation:

I'm gonna assume your assignment is to rewrite without negative exponents?

(6x^{-2}y^3)^{-3}

multiply the exponent into the parentheses, (a^{b} )^c = a^{bc}

(6x^{-2}y^3)^{-3} = 6^{-3} x^6y^{-9}

now move the negative exponents "downstairs"

6^{-3} x^6y^{-9} = \frac{x^6}{6^3*y^9}

negative exponents in denominator move up, in numerator move down

simplifying now

\frac{x^6}{6^3*y^9} = \frac{x^6}{216y^9}

the other way to do this is to move the entire inside down, then multiplying the exponent, like this

(6x^{-2}y^3)^{-3}=\frac{1}{(6x^{-2}y^3)^{3}} =\frac{1}{6^3*x^{-6}y^9}

then move things up and down

both ways will get you the same answer

Alchen [17]3 years ago
5 0

Answer:

nnalbn sjxNdcsfve

Step-by-step explanation:

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Find the y-intercept of a line parallel to 8x – 2y = 12 and passes through the point (5, 3).
Dmitry_Shevchenko [17]

Answer:

-17

Step-by-step explanation:

8x -2y= 12

<em>Divide</em><em> </em><em>the</em><em> </em><em>whole</em><em> </em><em>equation</em><em> </em><em>by</em><em> </em><em>2</em><em>:</em>

4x -y= 6

<em>Rewrite the equation into the slope-intercept form (y=mx+c, where m is the gradient while c is the y-intercept).</em>

-y= -4x +6

y= 4x -6

Thus, gradient of given line= 4.

Since parallel lines have the same gradient, gradient of line= 4.

y= 4x +c

<em>To find the y-intercept of the lone, substitute a pair of coordinates.</em>

When x=5, y=3,

3= 4(5) +c

3= 20 +c

c= 3 -20

c= -17

Thus, the y-intercept of the line is -17.

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3 years ago
Subtract 7 3/4 - 3 1/8. What's the answer?
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4 5/8 if u have a calculator there should be a abc button and that will help u subtract add etc with fractions and turn them into decimals if u need to
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PLS HELP ME ILL GIVE BRAINLIEST
kap26 [50]

Answer:

25

Step-by-step explanation:

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3 years ago
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<img src="https://tex.z-dn.net/?f=5x-%20%5Cdfrac%7B%20%5Csqrt%7B%209%20%7B%20x%20%7D%5E%7B%202%20%7D%20-6x%2B1%20%5Cphantom%7B%5
Morgarella [4.7K]

Answer:

=5x+1          or          =5x-1

Step-by-step explanation:

One is given the following equation:

5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

The problem asks one to simplify the expression, the first step in solving this equation is to factor the equation.  Rewrite the numerator and denominator of the fraction as the product of two expressions. Remember the factoring patterns:

(a-b)^2=a^2-2ab+b^2

=5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

=5x-\frac{\sqrt{(3x-1)^2}}{-(3x-1)}

Now simplify the numerator. Remember, taking the square root of a squared value is the same as taking the absolute value of the expression,

=5x-\frac{\sqrt{(3x-1)^2}}{1-3x}

=5x-\frac{|3x-1|}{-(3x-1)}

Rewrite the expression without the absolute value sign in the numerator. Remember the general rule for removing the absolute value sign:

|a-b|\\=a -b           or           (-a-b) = b-a

=5x-\frac{|3x-1|}{-(3x-1)}

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

Simplify both expressions, reduce by canceling out common terms in both the numerator and the denominator,

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

=5x-(-1)          or          =5x-(1)

Simplify further by rewriting the expression without the parenthesis, remember to distribute the sign outside the parenthesis by the terms inside of the parenthesis; note that negative times negative equals positive.

=5x-(-1)          or          =5x-(1)

=5x+1          or          =5x-1

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