If there is 2/3 of a bag of jelly beans and danny ate 1/4 of the bag last night what fraction of the bag is left
2 answers:
Answer: The fraction of the bag that left is
Step-by-step explanation: Given that there is a of a bag of jelly jeans and Danny ate
of the bag last night.
We are to find the fraction of the bag that left.
Let A be the fraction of the bag that is full of jelly beans and B be the fraction of the bag that Danny ate last night.
Then, according to the given information, we have
Therefore, the fraction of the bag that left is given by
Thus, the fraction of the bag that left is
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Answer:
5
Explanation:
1. Find a common denominator for the three fractions. A common denominator is a number all three numbers divide into evenly. The lowest common denominator for 4, 3, and 6 is 12.
2. Find the numerators. This can be done by multiplying the current numerators by however many times the old denominator goes into the new denominator.
4 goes into 12 3 times
3 goes into 12 4 times
6 goes into 12 2 times
1 x 3 = 3
2 x 4 = 8
1 x 6 = 6
So, the fractions become:
3. Add the numerators of the new fractions and keep the denominator the same.
4. Convert the improper fraction to a mixed number.
5. Finally, add the whole numbers.
1 + 4 = 5
9514 1404 393
Answer:
D
Step-by-step explanation:
If the actual value is above the value estimated from the tangent to the curve, then the curve must have a positive second derivative: it curves upward.
Only curve D in the second attachment has upward curvature.
Given:
Mason throws a coin 3 times.
The outcome of each throw is either Heads or Tails.
To find:
The list of all the possible outcomes of the 3 throws.
Solution:
Let H represents heads and T represents tails.
For each throw we have 2 choices either H or T.
For three throws the total number of possible outcomes is
Now, list the possible outcomes as shown below.
HHH, HHT, HTH, HTT, THH, THT, TTH, TTT
Therefore, the list of 8 possible outcomes is HHH, HHT, HTH, HTT, THH, THT, TTH, TTT.