SinB = cosC = AC / BC = 8/10 = 4/5;
tgB = ctg C = AC/AB = 8/6 = 4/3, because we use T. Pitagora for calculating AB;
sinC = cosB = AB/ BC = 6/10 = 3/5;
tgC = ctgB = AB/ AC = 6/8 = 3/4.
To find the correct function, just plug in 10 and 2 to see if the function equals zero with both numbers.
f(x)=x^2-12x+20
f(10)=100-120+20
f(10)=0 --> that's what we want, so let's check the other number
f(x)=x^2-12x+20
f(2)=4-24+20
f(2)=0 --> perfect. this function has zeros at both x=10 and x=2
The function that has zeros at both x=10 and x=2 is f(x)=x^2-12x+20.
To answer the question above, I let x be the number of calendars sold. You may use any other letter as this is just for representation. The total income generated in selling calendars is calculated by multiplying the number of calendars with the price. That is,
total income = 5x
If we let total income be y, our equation is further simplified into,
y = 5x
Answer:
y=-2x
Step-by-step explanation:
Because, let us take (-1,2)
2=-2(-1)
2=2
Similarly all the points show the same.
