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Yuliya22 [10]
3 years ago
7

Can i please have some help?

Mathematics
1 answer:
Allushta [10]3 years ago
3 0
Since you already have the perimeter, you can divide it to the total number of sides
156 cm / 12 sides
= 13 cm per sides
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8. Expand, then simplify: (2 Points) (2a – 3) (a2 + 3a - 5) ​
MA_775_DIABLO [31]

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3 0
3 years ago
How much would you need to deposit in an account now in order to have $2,500 in the account in 6 years? Assume the account earns
serious [3.7K]

Simple interest is computed using ...

... I = Prt . . . . . where P is the principal amount, r is the interest rate, and t is the lenght of time

The balance in the account is the principal plus the interest:

... P + I = P(1 + rt)

That balance is $2500, so we have

... $2500 = P(1 + 0.054·6) = 1.324P

... $2500/1.324 = P ≈ $1,888.22

The amount that must be deposited now is $1,888.22 in order for the balance to be $2,500 in 6 years.

7 0
3 years ago
Find the mean absolute deviation for each set of data:
aivan3 [116]

Answer:

1) 1.8

2) 1.7

Step-by-step explanation:

(for part A)

Mean: 3 + 5 + 6 + 3 + 2 + 2 + 1 + 0 + 0 + 4 + 7 + 4 + 5 + 5 + 6 = 53/15 = 3.5

3.5 - 3 = 0.5

3.5 - 5 = 1.5

3.5 - 6 = 2.5

3.5 - 3 = 0.5

3.5 - 2 = 1.5

3.5 - 2 = 1.5

3.5 - 1 = 2.5

3.5 - 0 = 3.5

3.5 - 0 = 3.5

3.5 - 4 = 0.5

3.5 - 7 = 3.5

3.5 - 4 = 0.5

3.5 - 5 = 1.5

3.5 - 5 = 1.5

3.5 - 6 = 2.5

mean absolute deviation: 0.5 + 1.5 + 2.5 + 0.5 + 1.5 + 1.5 + 2.5 + 3.5 + 3.5 + 0.5 + 3.5 + 0.5 + 1.5 + 1.5 + 2.5 = 27.5/15 = 1.8

(part B)

Mean: -3 + -2 + -1  + 0 + 1 + 2 + 3 = 0/7 = 0

0 - (-3) = 3

0 - (-2) = 2

0 - (-1) = 1

0 - 0 = 0

0 - 1 = 1

0 - 2 = 2

0 - 3 = 3

mean absolute deviation: 3 + 2 + 1 + 0 + 1 + 2 + 3 = 12/7 = 1.7

3 0
3 years ago
How many groups of 12 are in 600
Ugo [173]
Do 600÷12= 50

The answer is 50 
4 0
3 years ago
Read 2 more answers
In a certain population, body weights are normally distributed with a mean of 152 pounds and a standard deviation of 26 pounds.
Burka [1]


xBar ± z * sx / sqrt(n)

 

where xBar is the sample mean

z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α

sx is the sample standard deviation

n is the sample size

 

For sample size calcualtions we need the following. The width of the interval, from one end point to the center is:

 

z * sx / sqrt(n) =

 

w and solving for n gives:

 

<span> n = (z * sx / w) ^ 2 </span>

 

remember that n needs to be an integer. Always take the ceiling, i.e., round up. If you round down then the width of the interval will not be correct, it will be too wide. By rounding up, the interval will be more narrow than asked for, but this is a good thing. It means there is more precision in the estimate.

 

<span> here we have </span>

 

z = 2.05

w = 0.04 * 152 = 6.08

n = (z * sx / w) ^ 2 n = (2.05 * 26 / 6.08)^2

n = 76.8506

 

Round of the answer since n must be an integer.

 

<span>n = 77 </span>

7 0
4 years ago
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