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soldi70 [24.7K]

2 years ago

15

Can someone help me please

1 answer:

Dafna1 [17]2 years ago

3 0

Answer:

none

Explanation:

Fill in each option for x individually.

I) 9 $\leq$ -10 - 4(-1)

II) 9 $\leq$ -10 - 4(-3)

III) 9 $\leq$ -10 - 4(-2)

Then, simplify the right side of each inequality.

I) 9 $\leq$ -6

II) 9 $\leq$ 2

III) 9 $\leq$ -2

Each of these inequalities are flase. 9 is not less than or equal to any of these values, so the answer is none.

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The price of an item yesterday was $110 . Today, the price fell to $77 . Find the percentage decrease.

Andreas93 [3]

Subtract 110 dollars from 77 dollars to get your answer of 33 dollars

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2 years ago

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If Joe makes 16 out of 40 free throws in a

abruzzese [7]

The answer would be 6.4% because you have to do 16% of 40 and it will give you 6.4 and as a percent it is 640%

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3 years ago

The cable company takes an SRS of 250 of the approximately 15,000 households who subscribe to them. They found that 75 percent o

kati45 [8]

Answer:

Answer; Mean = p = 0.75

Standard deviation =0.0274

Step-by-step explanation:

Mean = p = 0.75

Standard deviation = √ [ p ( 1 - p) / n ]

= √ [ 0.75 * ( 1 - 0.75) / 250]

= 0.0274

5 0

3 years ago

Activity 4: Performance Task

Nookie1986 [14]

An arithmetic progression is simply a progression with a common difference among consecutive terms.

<em>The sum of multiplies of 6 between 8 and 70 is 390</em>
<em>The sum of multiplies of 5 between 12 and 92 is 840</em>
<em>The sum of multiplies of 3 between 1 and 50 is 408</em>
<em>The sum of multiplies of 11 between 10 and 122 is 726</em>
<em>The sum of multiplies of 9 between 25 and 100 is 567</em>
<em>The sum of the first 20 terms is 630</em>
<em>The sum of the first 15 terms is 480</em>
<em>The sum of the first 32 terms is 3136</em>
<em>The sum of the first 27 terms is -486</em>
<em>The sum of the first 51 terms is 2193</em>

<em />

<u>(a) Sum of multiples of 6, between 8 and 70</u>

There are 10 multiples of 6 between 8 and 70, and the first of them is 12.

This means that:

$\mathbf{a = 12}$

$\mathbf{n = 10}$

$\mathbf{d = 6}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{10} = \frac{10}2(2*12 + (10 - 1)6)}$

$\mathbf{S_{10} = 390}$

<u>(b) Multiples of 5 between 12 and 92</u>

There are 16 multiples of 5 between 12 and 92, and the first of them is 15.

This means that:

$\mathbf{a = 15}$

$\mathbf{n = 16}$

$\mathbf{d = 5}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{16}2(2*15 + (16 - 1)5)}$

$\mathbf{S_{16} = 840}$

<u>(c) Multiples of 3 between 1 and 50</u>

There are 16 multiples of 3 between 1 and 50, and the first of them is 3.

This means that:

$\mathbf{a = 3}$

$\mathbf{n = 16}$

$\mathbf{d = 3}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{16}2(2*3 + (16 - 1)3)}$

$\mathbf{S_{16} = 408}$

<u>(d) Multiples of 11 between 10 and 122</u>

There are 11 multiples of 11 between 10 and 122, and the first of them is 11.

This means that:

$\mathbf{a = 11}$

$\mathbf{n = 11}$

$\mathbf{d = 11}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{11}2(2*11 + (11 - 1)11)}$

$\mathbf{S_{11} = 726}$

<u />

<u>(e) Multiples of 9 between 25 and 100</u>

There are 9 multiples of 9 between 25 and 100, and the first of them is 27.

This means that:

$\mathbf{a = 27}$

$\mathbf{n = 9}$

$\mathbf{d = 9}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{9} = \frac{9}2(2*27 + (9 - 1)9)}$

$\mathbf{S_{9} = 567}$

<u>(f) Sum of first 20 terms</u>

The given parameters are:

$\mathbf{a = 3}$

$\mathbf{d = 3}$

$\mathbf{n = 20}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{20} = \frac{20}2(2*3 + (20 - 1)3)}$

$\mathbf{S_{20} = 630}$

<u>(f) Sum of first 15 terms</u>

The given parameters are:

$\mathbf{a = 4}$

$\mathbf{d = 4}$

$\mathbf{n = 15}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{15} = \frac{15}2(2*4 + (15 - 1)4)}$

$\mathbf{S_{15} = 480}$

<u>(g) Sum of first 32 terms</u>

The given parameters are:

$\mathbf{a = 5}$

$\mathbf{d = 6}$

$\mathbf{n = 32}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{32} = \frac{32}2(2*5 + (32 - 1)6)}$

$\mathbf{S_{32} = 3136}$

<u>(g) Sum of first 27 terms</u>

The given parameters are:

$\mathbf{a = 8}$

$\mathbf{d = -2}$

$\mathbf{n = 27}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{27} = \frac{27}2(2*8 + (27 - 1)*-2)}$

$\mathbf{S_{27} = -486}$

<u>(h) Sum of first 51 terms</u>

The given parameters are:

$\mathbf{a = -7}$

$\mathbf{d = 2}$

$\mathbf{n = 51}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{51} = \frac{51}2(2*-7 + (51 - 1)*2)}$

$\mathbf{S_{51} = 2193}$

Read more about arithmetic progressions at:

brainly.com/question/13989292

4 0

1 year ago

Read 2 more answers

What is the measure of EAB in circle F?<br> 72°<br> 92°<br> 148°<br> 200°

Arada [10]

We have been given a diagram. We are asked find the measure of arc EAB.

First of all, we will find the measure of arcs ED and CB using our given information.

We know that measure of an inscribed angle is half the measure of intercepted arc.

We can see that angle EBC is inscribed angle of arc EDC, so measure of arc EDC will be twice the measure of angle EBC.

$\widehat{EDC}=2\times m\angle EBC$

$\widehat{EDC}=2\times 80^{\circ}$

$\widehat{EDC}=160^{\circ}$

Similarly, we will find the measure of arc DCB.

$\widehat{DCB}=2\times m\angle DEB$

$\widehat{DCB}=2\times 70^{\circ}$

$\widehat{DCB}=140^{\circ}$

$\widehat{ED}=\widehat{EDC}-\wdiehat{DC}$

$\widehat{ED}=160^{\circ}-88^{\circ}$

$\widehat{ED}=72^{\circ}$

$\widehat{ED}+\widehat{DCB}+\widehat{EAB}=360^{\circ}$

$72^{\circ}+140^{\circ}+\widehat{EAB}=360^{\circ}$

$212^{\circ}+\widehat{EAB}=360^{\circ}$

$\widehat{EAB}=360^{\circ}-212^{\circ}$

$\widehat{EAB}=148^{\circ}$

Therefore, the measure of arc EAB is 148 degrees and option C is the correct choice.

8 0

3 years ago

Read 2 more answers