Answer:
m∠ABD = 88º
m∠CBD = 23º
Step-by-step explanation:
(-10x + 58) + (6x + 41) = 111
Combine like terms
-4x + 99 = 111
Subtract 99 from both sides
-4x = 12
Divide both sides by -4
x = -3
------------------------
m∠ABD = -10x + 58
m∠ABD = -10(-3) + 58
m∠ABD = = 30 + 58
m∠ABD = 88º
m∠CBD = 6x + 41
m∠CBD = 6(-3) + 41
m∠CBD = -18 + 41
m∠CBD = 23º
We start with the more complicated side which is the left side, and show that, on using some trigonometric identities, we will get the term on the right side .

Using Quotient identity for tangent function, we will get


Taking out sine function from the numerator

Cancelling the common term of numerator and denominator

Answer:
The roots of equations are as m =
And n =
Step-by-step explanation:
The given quadratic equation is 2 x² + 6 x - 1 = 0
This equation is in form of a x² + b x + c = 0
Let the roots of the equation are ( m , n )
Now , sum of roots = 
And products of roots = 
So, m + n =
= - 3
And m × n = 
Or, (m - n)² = (m + n)² - 4mn
Or, (m - n)² = (-3)² - 4 (
)
Or, (m - n)² = 9 + 2 = 11
I.e m - n = 
Again m + n = - 3 And m - n = 
Solving this two equation
(m + n) + ( m - n) = - 3 + 
I.e 2 m = - 3 + 
Or, m = 
Similarly n =
Hence the roots of equations are as m =
And n =
Answer
Answer:
16
Step-by-step explanation:
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