Answer:
They don’t 12+16+20= 48
12 x 16 x 20= 3840
Step-by-step explanation:
Answer:
Multiply both sides by 11 to isolate the variable.
Step-by-step explanation:
a = 55
Answer:
I think like expressions you use x or y or such many variables. you use - or + too. like (x+2)y there are parentheses too.
Answer:
Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.
Step-by-step explanation:
We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.
Let us find amount of fuel used by autos by dividing the total distance by their mileage.
![\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}](https://tex.z-dn.net/?f=%5Ctext%7BFuel%20used%20by%201st%20auto%7D%3D%5Cfrac%7B%5Ctext%7B%20600%20miles%7D%7D%7B%5Cfrac%7B%5Ctext%7B%2020%20miles%7D%7D%7B%5Ctext%7Bgallon%7D%7D%7D)
![\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}](https://tex.z-dn.net/?f=%5Ctext%7BFuel%20used%20by%201st%20auto%7D%3D%5Cfrac%7B%5Ctext%7B%20600%20miles%7D%7D%7B%5Ctext%7B%2020%20miles%7D%7D%5Ctimes%20%5Ctext%7Bgallon%7D)
![\text{Fuel used by 1st auto}=30 \text{ gallons}](https://tex.z-dn.net/?f=%5Ctext%7BFuel%20used%20by%201st%20auto%7D%3D30%20%5Ctext%7B%20gallons%7D)
![\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}](https://tex.z-dn.net/?f=%5Ctext%7BFuel%20used%20by%202nd%20auto%7D%3D%5Cfrac%7B%5Ctext%7B%20600%20miles%7D%7D%7B%5Cfrac%7B%5Ctext%7B%2030%20miles%7D%7D%7B%5Ctext%7Bgallon%7D%7D%7D)
![\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}](https://tex.z-dn.net/?f=%5Ctext%7BFuel%20used%20by%202nd%20auto%7D%3D%5Cfrac%7B%5Ctext%7B%20600%20miles%7D%7D%7B%5Ctext%7B%2030%20miles%7D%7D%5Ctimes%20%5Ctext%7Bgallon%7D)
![\text{Fuel used by 2nd auto}=20 \text{ gallons}](https://tex.z-dn.net/?f=%5Ctext%7BFuel%20used%20by%202nd%20auto%7D%3D20%20%5Ctext%7B%20gallons%7D)
Let us find the difference of fuel used by both autos.
![\text{Number of gallons that 2nd auto used less than 1st auto}=30-20](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20gallons%20that%202nd%20auto%20used%20less%20than%201st%20auto%7D%3D30-20)
![\text{Number of gallons that 2nd auto used less than 1st auto}=10](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20gallons%20that%202nd%20auto%20used%20less%20than%201st%20auto%7D%3D10)
Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces
pounds of carbon.
Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.
Answer:
2,674.14 g
Step-by-step explanation:
Recall that the formula for radioactive decay is
N = N₀ e^(-λt)
where,
N is the amount left at time t
N₀ is the initial amount when t=0, (given as 42,784 g)
λ = coefficient of radioactive decay
= 0.693 ÷ Half Life
= 0.693 ÷ 18
= 0.0385
t = time elapsed (given as 72 years)
e = exponential constant ( approx 2.7183)
If we substitute these into our equation:
N = N₀ e^(-λt)
= (42,787) (2.7183)^[(-0.0385)(72)]
= (42,787) (2.7183)^(-2.7726)
= (42,787) (0.0625)
= 2,674.14 g