Is it possible to make an eight-pointed star out of quilt pieces with two angles of 130?

28 in 21 in., 20 in.<br> Is this a right triangle?

ankoles [38]

Answer:

No, it is not a right triangle.

Step-by-step explanation:

The simplest way to determine is testing out the numbers with Pythagorian theorem.

If it complies with the theorem, it is a right triangle.

let's assume c = 28, b = 21, and a = 20

the longest side is the hypotenuse so side c (28 in) will be the hypotenuse.

According to the Pythagorian theorem, the square of the length of hypotenuse must equal to the sum of squares of other two sides.

check:

c^2 = 28^2 = 784

a^2 + b^2 = 21^2 + 20^2 = 841

because c^2 is not equal to a^2 + b^2, the triangle is not a right triangle.

7 0

3 years ago

What 3/16 turned into a decimal and 5/48 turned into a decimal

Ira Lisetskai [31]

A way to do it is like this. Numerator divided by denominator so 3 divided by 16 which is .187.

5 divided by 48 is .0146 with the six repeating

7 0

3 years ago

Read 2 more answers

A bag contains 40 marbles. The probability of selecting a red marble at random is 1/5. How many red marbles are in the bag?

goblinko [34]

Answer:

8 red marbles.

Step-by-step explanation:

All together we have 40 marbles. The fraction of marbles that are red is 1/5 which means that we should divide the total number of marbles, which is 40 by the denominator ( Bottom number of fraction ) 5 so that we get the number of groups that have 1 red marble in them. In this case we have 8 groups.

40/5=8

You always divide by the denominator ( Bottom number of fraction ) first and then you multiply your answer by the numerator ( Top number of fraction ) .

If each group has 1 red marble in it and we have 8 groups, it means that we have 8 red marbles in the bag.

1 * 8 = 8 red marbles in the bag

If the numerator (number above the fraction line) was more than one, then this would mean that we have more than 1 marble in each group of marbles.

Example:

If we had 3/5 we would have 3 marbles in each group of marbles. This means that instead of doing 1 * 8 we would have to do 3 * 8 = 24. We would have 24 red marbles in the bag.

Easy and quick way if you do not need the explanation:

Another way we could do this is by simply multiplying the fraction ( 1/5 ) by the total number of marbles ( 40 ). This would still give us an answer of 8 red marbles in the bag. 40/5=8, 8*1=8

7 0

3 years ago

Look at the image below plz correct answers Surface area of cones 15 points

monitta

Answer:

$A\approx 282.7\ m^2$

Step-by-step explanation:

1. Approach

The easiest method to solve this problem is to use the Pythagorean theorem to find the height of the cone. Then one can substitute the values given and found on the cone into the formula to find the surface area in order to solve for the surface area of the given cone.

2. Height of the cone

Imagine drawing a line from the tip of the cone down to the center of the base. This line will form a right angle with the base, thus, a right triangle is formed between the line, the radius (the distance from the center to the circumference or outer edge on a circle) of the base, and the incline of the cone. The Pythagorean theorem is a formula that relates the sides of a right triangle. This formula is as follows:

$a^2+b^2=c^2$

Where (a) and (b) are the legs or the sides adjacent to the right angle of the right triangle, and (c) is the hypotenuse or the side opposite the right angle of the right triangle. Substitute the given values into the formula and solve for the unknown, or rather the height of the cone:

$a^2+b^2=c^2$

$a^2+5^2=13^2$

Simplify,

$a^2+5^2=13^2$

$a^2+25=169$

Inverse operations,

$a^2+25=169$

$a^2=144$

$a=12$

$h=12$

3. Find the surface area of the cone.

The following formula can be used to find the surface area of a cone:

$A=\pi r(r+\sqrt{h^2+r^2})$

Where ( $\pi$ ) represents the numerical value (3.1415...), (r) represents the radius of the base, and (h) represents the height of the cone. Substitute the given values into the formula and solve for the surface area: