The total number of coins is 9. Therefore
p+n+d = 9 (1)
There are two fewer nickels than dimes. Therefore
n = d - 2 (2)
From (1) and (2), obtain
p+(d-2)+d = 9
p + 2d = 11
p = 11 - 2d (3)
Total value:
0.01p + 0.05n + 0.10d = 0.53 (4)
Substitute (2) and (3) into (4).
0.01(11-2d) + 0.05(d-2) + 0.10d = 0.53
0.11 - 0.02d + 0.05d - 0.10 + 0.10d = 0.53
0.03d + 0.01 = 0.53
0.13d = 0.52
d = 4
p = 11 - 2d = 11 - 8 = 3
Answer: 3 pennies
=(y2-3y-5)-(-y2-7y+4)
=y2-3y-5+y2+7y-4
=2y2+4y-9
Hope this helps! :)
C-18
√324= √2^2•3^4= √2^2•√3^2•3^2= √2^2•√3^2•√3^2=2•3•3=18
Answer:
-1/2
Step-by-step explanation:
