Y varies directly with x" means y = constant * x or y = kx ----- (1)1. when x = -1/2, y = 2Put it in (1):2 = k * (-1/2)multiply by 2:4 = k * (-1)4 = -kk = -4y = -4x
"find the value of y when x= -0.3"y = -4x = (-4) * (-0.3) = 1.2
So for each problem, start with y = kxThey give you one x and one y value.Put it in y = kx and find k.Then put x = -0.3 and find y.
You can solve mean by adding up all the numbers then dividing it by the number of numbers there are.
You can solve the median by putting all of the numbers in order and then crossing off one in the beginning then crossing off one at the end. You can continue that until you get to one number in the middle.
You can solve the mode by looking for the most frequent number. That's the mode. You can remember that by looking at the MO and remember most often.
I hope this helps :-)
Step-by-step explanation:
please mark me as brainlest
The triangles ABC and EDF are congruent, meaning they have the same side lengths and angles measures.
The measure of DF, as both triangles are congruent, is equal to the measure of BC.
We can calculate the length of BC using the distance formula:
![\begin{gathered} D=\sqrt[]{(x_c-x_b)^2+(y_c-y_b_{})^2} \\ D=\sqrt[]{(2-2)^2+(-1-4)^2} \\ D=\sqrt[]{0^2+(-5)^2} \\ D=\sqrt[]{(-5)^2} \\ D=|-5| \\ D=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%3D%5Csqrt%5B%5D%7B%28x_c-x_b%29%5E2%2B%28y_c-y_b_%7B%7D%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%282-2%29%5E2%2B%28-1-4%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B0%5E2%2B%28-5%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%28-5%29%5E2%7D%20%5C%5C%20D%3D%7C-5%7C%20%5C%5C%20D%3D5%20%5Cend%7Bgathered%7D)
As BC is congruent with DF and BC=5, the length of DF is 5 units.
