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3 years ago

Jill wants to solve the following system using the elimination method:

Mathematics

2 answers:

Mariulka [41]3 years ago

8 0

Answer:

-3

Step-by-step explanation:

To use the elimination method, we need the variable we want to eliminate to have the same coefficient number in both equations, but with the opposite sign. Thus, when adding the equations that variable will be eliminated.

The variable x in the first equation is the following:

and the x in the second equation is:

So we must multiply the first equation by -3, so it becomes:

-3y = -3x + 8

and we can see that now, the x's in both equation have the same coefficient number but a different sign (one positive and one negative) which is what we need to apply the elimination method.

asambeis [7]3 years ago

5 0

-3 as in the first equation x = 1x so multiply it by -3 you’ll get -3x.

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135% as a fraction or a mixed number fully simplified please

solong [7]

Answer:

135% = 27/20 = 17/20 as a fraction

Step-by-step explanation:

Step 1: Write down the percent divided by 100 like this:

135% = 135/100

Step 2: Multiply both top and bottom by 10 for every number after the decimal point:

As 135 is an integer, we don't have numbers after the decimal point. So, we just go to step 3.

Step 3: Simplify (or reduce) the above fraction by dividing both numerator and denominator by the GCD (Greatest Common Divisor) between them. In this case, GCD(135,100) = 5. So,

(135÷5)/(100÷5) = 27/20 when reduced to the simplest form.

As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 135/100 is also equal to 1 7/20 when expressed as a mixed number.

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There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t

beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways $=(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})$

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

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