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Aleks04 [339]
2 years ago
7

What is the y-intercept in the equation y = 4x - 3?

Mathematics
2 answers:
RSB [31]2 years ago
6 0

-3. The y-intercept is the last number that is being added or subtracted.

maw [93]2 years ago
3 0

Answer:

-3

Step-by-step explanation:

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I need c and d answered badly
Kisachek [45]

C. translated down 2 units

---The "-2" located on the outside of f(x) tells us that the y-values are being changed. With that, the graph can be moved up or down. The presence of the negative/subtraction sign tells us that the graph is moved down.

D. translated right 4 units

---The "-4" located with the x in f(x) tells us that the x-values are being changed. The only tricky thing about this is that the direction of the movement is actually the opposite of the sign. So with the negative/subtraction sign, the graph is moved to the right instead of the left.

Hope this helps!

3 0
2 years ago
Simplify the polynomial(-8×)+×+(-2×)​
Morgarella [4.7K]

Answer:

-9x

Step-by-step explanation:

Without the confusing parentheses, this "polynomial" becomes -8x + x -2x. If we take 2 away from -8, it becomes -10. If we add a positive x, it becomes -9x. Therefore, the answer is (the monomial) -9x.

8 0
3 years ago
Read 2 more answers
An object has an area of 12 square centimeters. what could the length and width be
LUCKY_DIMON [66]
The length and width can 6 and 2 or 3 and 4.
example: 3x4=12
6x2=12
3 0
3 years ago
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Find the area of the shape shown below ​
Arlecino [84]

Answer: 12.5

Step-by-step explanation:

area= 1/2 (2.5+7.5) 2.5

sorry if its not clear enough i dont really know how else to explain it

7 0
3 years ago
Read 2 more answers
explain why the function f(x)= 5x-15/x-3 is not asymptotic to the line x=3. sketch the graph of this function.
Katyanochek1 [597]
X=3 is a vertical line . The question is "Is this line a vertical asymptotefor the function f(x)?". Vertical asymptote is vertical line near which the function grows without bound.
The function f(x)=5x-15/x-3 is not asymptotic to the line x=3, because for x=3 f(x)=5*3-15/3-3=0/0=0 . So, there is a value for x=3 and the function f(x) does not grow near x=3 without bound.

3 0
3 years ago
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