the functions of f and g are given by f(x)=6x+8and g(x)=x-2 over 3. An expression for gf(x) in its simplest form

Mathematics

1 answer:

dmitriy555 [2]3 years ago

4 0

Answer:

gf(x) = (6x+6)/3

Step-by-step explanation:

replace f(x) in x on g(x)..then you get the answer

You might be interested in

If the orientation of two shapes is not the same, which transformation(s) should you use to show they are congruent? Why?

Aleksandr-060686 [28]

Answer:

The answer is below

Step-by-step explanation:

Transformation s the movement of a point from its initial location to a new location. If an object is transformed, the all its points are also transformed. Types of transformation are rotation, reflection, translation and dilation.

Two shapes are congruet if they have the same shape and size, two objects are congruent if they can be moved without changing their shape or size. Congruent transformations are transformation that create congruent objects. The three types are:

Translation: sliding an object either up, down, left or right.
Reflection: Flipping an object over a line
Rotation: turning an object about a point

4 0

3 years ago

Read 2 more answers

000

grigory [225]

Answer:

Step-by-step explanation:

4 0

3 years ago

What is the constant term of the quotient when 2x^3-3x^2 + 4x-2 is divided by x^2-x+2?

AlladinOne [14]

Answer:

-1

Step-by-step explanation:

See the attachment for the polynomial long division. The constant in the quotient is -1.

_____

Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.

That could be a first guess in a "guess and check" solution approach.

<em>Guess</em>: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).

<em>Check</em>: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2

Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.