All categories

3 years ago

the functions of f and g are given by f(x)=6x+8and g(x)=x-2 over 3. An expression for gf(x) in its simplest form

Mathematics

1 answer:

dmitriy555 [2]3 years ago

4 0

Answer:

gf(x) = (6x+6)/3

Step-by-step explanation:

replace f(x) in x on g(x)..then you get the answer

You might be interested in

Solve each system of equations algebraically. For each one, explain what the solution (or lack thereof) tells you

Paul [167]

Answer:

a: no solutions

b: (2, 3)

Step-by-step explanation:

In both equations, the slope of x is the same, but the y-intercept is not, which means they are parallel. Therefore, this system of equations has no solutions.

Since both of the equations are equal to y, we can set them equal to each other:

$\frac{1}{2}x^2+1= 2x-1\\x^2 + 2 = 4x - 2\\x^2-4x+4=0$

We can solve by factoring (by finding a number that multiplies to 4 and adds up to -4):

(x-2)^2 = 0

x = 2

Now, to find y, plug-in x to any of the equations:

y = 2*2-1 = 3

Therefore, the solution to this system of equation is (2, 3)

I hope this helped.

4 0

3 years ago

Annie walks 15 feet away from her house and places a mirror on the ground. She backs 4 feet away from the mirror so that she can

balandron [24]

9 is the answer to your Q

5 0

3 years ago

During a sale, a dress is marked down from a selling price of $80 to a sale price of $60. What is the percent markdown

Zanzabum

$80 x .25 = 20

$80-20=$60

25% markdown

5 0

3 years ago

OOOO

lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

$x^4+95x^2 -500=0$

Substituting $x^2=a,$ given bi-quadratic equation reduces in the form of following quadratic equation:

$a^2 +95a -500=0\\$

Let us factorize the above quadratic equation:

$a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\$

Since square root of a negative number cannot be found, so:

$x \neq \pm \sqrt{-100}\\$

$CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\$

3 0

3 years ago

Every third visitors to a museum gets a free bumper sticker. Every fifth visitor to that museum gets a free key chain. Which vis

Rashid [163]

The fifteenth customer will be the first because 5x3=15

8 0

3 years ago