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3 years ago

14

the functions of f and g are given by f(x)=6x+8and g(x)=x-2 over 3. An expression for gf(x) in its simplest form

1 answer:

dmitriy555 [2]3 years ago

4 0

Answer:

gf(x) = (6x+6)/3

Step-by-step explanation:

replace f(x) in x on g(x)..then you get the answer

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every fourth visitor to a museum gets a free bumper sticker every tent visitor to the museum gets a free keychain which visitor

ioda

The 20th visitor will be the first to get both the key chain and the bumper sticker, I found this out by finding the least common multiple, or LCM, you do this by writing out the multiples of both 4 and 10, 4 8 12 16 20..... and 10 20 30... then you find the smallest number that both 4 and 10 have in common. I hope this helps, sorry if it doesn't.

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3 years ago

If 45% of a number g is 225 what is 74% of g

Gelneren [198K]

370
You first have to divide 225 by 45 and then multiply by 74

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3 years ago

Round to the nearest thousandth.<br> 1.0835

Ne4ueva [31]

Answer:

It would be 1.084

5 0

3 years ago

Read 2 more answers

Students have organized

Olenka [21]

Answer:

Part A. At least 6 hours

Part B. In less than 2.5 hours Elijah will be behind Mercedes

Part C. In more than 2.5 hours Elijah will be ahead Aubrey

Step-by-step explanation:

D = distance

v =speed

t = time

Formula connecting D, v and t:

$D=v\cdot t$

Part A.

Steve's speed: $v=3.5\ mph$

Distance: at least 21 miles

Time: unknown, so

$3.5\cdot t\ge 21\\ \\35t\ge 210\ [\text{Multiplied by 10}]\\ \\t\ge \dfrac{210}{35}\\ \\t\ge \dfrac{30}{5}\\ \\t\ge 6$

It would take Steve at least 6 hours to walk at least 21 mi on Day 1.

Part B.

Mercedes's speed: $v_M=2.4\ mph$

Elijan's speed: $v_E=3.2\ mph$

Elijan's Distance walked: $D_E$ miles

Mercedes's Distance walked: $D_M$ miles

Time: x hours

Mercedes is 2 miles ahead, so

$D_E=3.2x\\ \\D_M=2.4x+2$

Elijan will be behind when

$D_E$

In 2.5 hours Elijan will catch up Mercedes, and in less than 2.5 hours Elijah will be behind Mercedes.

Part C.

Aubrey's speed: $v_M=3\ mph$

Elijan's speed: $v_E=3.2\ mph$

Elijan's Distance walked: $D_E$ miles

Aubrey's Distance walked: $D_A$ miles

Time: x hours

At the beginning of Day 3, Elijah starts walking at the marker for Mile 42, and Aubrey starts walking at the marker for Mile 42.5.

$D_E=42+3.2x\\ \\D_A=42.5+3x$

Elijan will be ahead of Aubrey when

$D_E>D_A\\ \\42+3.2x> 42.5+3x\\ \\3.2x-3x>42.5-42\\ \\0.2x>0.5\\ \\2x>5\ [\text{Multiplied by 10}]\\ \\x>\dfrac{5}{2}\\ \\x>2.5\ hours$

In 2.5 hours Elijan will catch up Aubrey, and in more than 2.5 hours Elijah will be ahead Aubrey.

4 0

4 years ago

ANSWER IN THE COMMENTS SECTION

ryzh [129]

Answer:

B.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers