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Luden [163]
3 years ago
8

Solve the inequality 1/6 w≥2.5

Mathematics
2 answers:
ale4655 [162]3 years ago
6 0

Answer:w is equal or more than 15

Step-by-step explanation:

SSSSS [86.1K]3 years ago
3 0

Answer:

w≥15

Step-by-step explanation:

If the equation is \frac{1}{6}w≥2.5, first, you need to try and get the variable by itself. To do that, you can multiply both sides by 6, to cancel the 1/6. So, 2.5 multiplied by 6 equals 15. You're left with w\geq 15

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The table and equation below show the proportional relationship between time, in seconds, x, and distance traveled, in feet, y,
yarga [219]

Answer:

Step-by-step explanation:

8 0
2 years ago
A coach is assessing the correlation between the number of hours spent practicing and the average number of points scored in a g
cricket20 [7]

Answer:

a) r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

b) m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

c) For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

Step-by-step explanation:

We have the following data:

Number of hours spent practicing (x) 0 0.5 1 1.5 2 2.5 3 3.5 4

Score in the game (y) 5 8 11 14 17 20 23 26 29

Part a

The correlation coefficient is given:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=9 \sum x = 18, \sum y = 153, \sum xy = 396, \sum x^2 =51, \sum y^2 =3141  

r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=51-\frac{18^2}{9}=15  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=396-\frac{18*153}{9}=90  

And the slope would be:  

m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

Part c

For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

5 0
3 years ago
Use the multiplication rule to find the probability that the first four guesses are wrong and the fifth is correct. That is, fin
BabaBlast [244]

Complete question is;

Multiple-choice questions each have 5 possible answers, one of which is correct. Assume that you guess the answers to 5 such questions.

Use the multiplication rule to find the probability that the first four guesses are wrong and the fifth is correct. That is, find P(WWWWC), where C denotes a correct answer and W denotes a wrong answer.

P(WWWWC) =

Answer:

P(WWWWC) = 0.0819

Step-by-step explanation:

We are told that each question has 5 possible answers and only 1 is correct. Thus, the probability of getting the right answer in any question is =

(number of correct choices)/(total number of choices) = 1/5

Meanwhile,since only 1 of the possible answers is correct, then there will be 4 incorrect answers. Thus, the probability of choosing the wrong answer would be;

(number of incorrect choices)/(total number of choices) = 4/5

Now, we want to find the probability of getting the 1st 4 guesses wrong and the 5th one correct. To do this we will simply multiply the probabilities of each individual event by each other.

Thus;

P(WWWWC) = (4/5) × (4/5) × (4/5) × (4/5) × (1/5) = 256/3125 ≈ 0.0819

P(WWWWC) = 0.0819

4 0
3 years ago
Substitute the value n = 4 in the expressions<br><br>2n<br>n + 2<br>3(n+4)​
Lelu [443]

Step-by-step explanation:

Given n = 4

2n = 2* 4= 8

n + 2 = 4 + 2 = 6

3(n + 4) = 3( 4 + 4) = 3 * 8 = 24

Hope it will help :)

4 0
2 years ago
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