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Sliva [168]
3 years ago
12

Solving a quadratic equation by completing the square. De

Mathematics
1 answer:
postnew [5]3 years ago
8 0

Answer:

x1, x2 = 7.73 , 4.27

Step-by-step explanation:

To find the roots of a quadratic function we have to use the bhaskara formula

ax^2 + bx + c

x^2 - 12x + 33

a = 1     b = -12    c = 33

x1 = (-b + √ b^2 - 4ac)/2a

x2 =(-b - √ b^2 - 4ac)/2a

x1 = (12 + √(-12^2 - (4 * 1 * 33))) / 2 * 1

x1 = (12 + √(144 - 132)) / 2

x1 = (12 + √12) / 2

x1 = (12 + 3.46) / 2

x1 = 15.46 / 2

x1 = 7.73

x2 = (12 - √(-12^2 - (4 * 1 * 33))) / 2 * 1

x2 = (12 - √(144 - 132)) / 2

x2 = (12 - √12) / 2

x2 = (12 - 3.46) / 2

x2 = 8.54 / 2

x2 = 4.27

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2 years ago
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3 years ago
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s344n2d4d5 [400]

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Step-by-step explanation:

7 0
3 years ago
What is the distance in units between (−11, −20) and (−11, 5)
Morgarella [4.7K]
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6 0
3 years ago
Read 2 more answers
How does f(x) = 3* change over the interval x = 4 to x = 57
Vilka [71]

f(x) increase by a factor of 3

Explanation:

        Given that f(x)= 3* and the interval is x=4 to x=57

        Now we put the value for x is 4 to 57 then value of f(x) increase with the multiply of 3.

        Because the x is multiplied with 3 i.e., 3*

        So f(x) increase by a factor of 3.

        If we put x=4, then f(x)= 12     (∵ 3×4=12)

        If we put x=5, the f(x)= 15       (∵ 3×5=15)

        If we put x=6,the f(x)= 18             (∵ 3×6=18)

similarly., values of x= 7,8,9,...155.

        Then,

        If we put x=56, the f(x)=168

        This process will continue until f(x)=171 for x=57.

6 0
3 years ago
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