Answer:
x1, x2 = 7.73 , 4.27
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 12x + 33
a = 1 b = -12 c = 33
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (12 + √(-12^2 - (4 * 1 * 33))) / 2 * 1
x1 = (12 + √(144 - 132)) / 2
x1 = (12 + √12) / 2
x1 = (12 + 3.46) / 2
x1 = 15.46 / 2
x1 = 7.73
x2 = (12 - √(-12^2 - (4 * 1 * 33))) / 2 * 1
x2 = (12 - √(144 - 132)) / 2
x2 = (12 - √12) / 2
x2 = (12 - 3.46) / 2
x2 = 8.54 / 2
x2 = 4.27
Answer: 10, 10sqrt(2)
C
So this one is pretty much like the last one
the distance on the x values is 6 and the distance on the y values is 4
1/6 of 6 is 1 and 1/6 of 4 is .66
We subtract the coordinates from R
4-1 is 3
2 -.66 =1.33
The 1/6 point is at (-3,1.33)
Answer: Y-intercept:(0,3)
x-intercept:(-1.5,0)
0.24510
