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vagabundo [1.1K]
3 years ago
9

Suppose that 62 percent of the graduates from your high school go on to four-year colleges, 15 percent go on to two-year college

s, 18 percent find employment, and the remaining graduates search for a job. If a randomly selected student is not going on to a four-year college, what is the probability he or she will find employment?a) .44b) .474c) .526d) .545e) .565
Mathematics
1 answer:
inn [45]3 years ago
3 0

Answer:

b) .474

Step-by-step explanation:

If 62% go to a four-year college, that means that those who don't represent 38% of the high-school graduates.

You pick up someone who is NOT going to a four-year college (so, he's among the 38%)... what's the chance he's in the 18% of the whole high-school graduates population that found a job?

To calculate that probability, we have to divide 18% by 38%.

P = 18% / 38% = 0.4736, so 0.474

Since we are sure he doesn't go to a four-year college, there's 47.4% of chances he finds a job.

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Every day, Michael consumes 4 more ounces than the pretzels. Multiply 5 by 4 to recieve the answer:

4 x 5 = 20

So the answer is A.

7 0
2 years ago
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A=20×(1+0.025÷2)^(2×30)
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8 0
3 years ago
Jason can read 850 words in 5 minutes. Ashley can read 804 words in 4 minutes. Who reads at a faster pace per minut
Vedmedyk [2.9K]
850/5=170
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8 0
3 years ago
the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years​
Yuliya22 [10]

Answer:  125 g

<u>Step-by-step explanation:</u>

A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k

\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125

8 0
3 years ago
Joshua uses his thermometer and finds the boiling point of ethyl alcohol to be 75 degrees Celsius. He looks in a reference book
MissTica

Answer:

6.25%

Step-by-step explanation:

Percent error is calculated by taking the difference of measured value and correct value divided by correct value and multiplied by 100%.

Mathematically,

Percent error = (correct value - measured value)/correct value  * 100%

_________________________________________________

in the problem given

measured value = 75 degrees Celsius

correct value = 80 degrees Celsius ( as given in reference book)

thus,

Percent error = (80 - 75)/80 * 100%

Percent error = (5/80 )* 100% = 6.25%

Percent error calculated by him is  6.25%.

4 0
3 years ago
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