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3 years ago

Find the measure of angle angle AEB in the figure below. Enter only the number. PLEASE HELP ASAP

Mathematics

2 answers:

Dafna1 [17]3 years ago

8 0

Answer:

42°

Step-by-step explanation:

AD is a line

AEC and DEC are both 90°

AEB and CEB make up 90°

AEB+CEB=AEC substitute

AEB+48=90 Next use Subtraction property of equality

AEB=42

Hope this helps, if so please give me brainliest, it helps a lot. :)

Have a good day!

qwelly [4]3 years ago

5 0

Answer:

∠AEB=42

Step-by-step explanation:

∠AEB and ∠BEC are inside of ∠AEC.

∠AEC is a right angle, Since ∠AEC and ∠CED are on a straight line, they must add to 180 degrees. ∠CED is a right angle (the little square in the corner tell us this), so ∠AEC must also be a right angle. This is because a right angle is 90 degrees (∠CED+∠AEC=180 --> 90+∠AEC=180 --> ∠AEC=90)

Therefore, the 2 angles (AEB and BEC) inside of ∠AEC must add to 90 degrees.

∠AEB+ ∠BEC= 90

We know that ∠BEC=48

∠AEB+48=90

We want to find out what ∠AEB is. We must get ∠AEB by itself. 48 is being added, and the inverse of addition is subtraction. Subtract 48 from both sides.

∠AEB+48-48=90-48

∠AEB=90-48

∠AEB=42

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Step-by-step explanation:

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3 years ago

3/10 divided by -1/3

Snezhnost [94]

Answer:

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Step-by-step explanation:

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3 years ago

The points on the graph of the function y=3+f(x-1) can be obtained from the points on y=f(x) by a shift of:

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3 years ago

Point Q was rotated by -150° (the center of rotation is indicated).

DedPeter [7]

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3 years ago

Graph each piecewise function. Then Identify the properties.

Mazyrski [523]

Answer:

The domain is:

x: (-∞, 0] U (0, ∞)

The range is

y: [0, ∞)

Step-by-step explanation:

These types of functions are known as piecewise functions. It has two pieces of functions, you must graph both pieces for each interval.

First, graph:

y = -x for x from -∞ to x = 0

Note that y = -x is the equation of a negative slope line = -1 that passes through the origin

Second, graph:

y = x for x from x = 0 to ∞

Note that y = x is the equation of a positive slope line = 1 that passes through the origin.

The graph of this function is shown in the attached image. Note that it matches the absolute value graph of x.

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In this function y it is always positive, and x can be any real number.

Therefore the domain is:

x: (-∞, 0] U (0,∞)

The range is:

y: [0, ∞)

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3 years ago